Let
. The tangent plane to
at (1, 2, -6) has equation

We have

Then the tangent plane has equation

Let
, and
. The tangent plane to
at a point
is

We have

so that this plane has equation

In order for this plane to be parallel to the previous plane, we need to have

so the point we're looking for is (2, 6, -36).
Answer:
52
Step-by-step explanation:
Evaluting an expression basically means to multiply the numbers given.
In this certain question, we are just multiplying 13 by 4 which would give us the result of 52.
Answer:
120000000000000000
Step-by-step explanation:
1.2*10^17