<span>if 35% or 0.35 say no, to compute the probability that at least one of 7 </span>called a talk show while under the influence of peer pressure <span> is (1-0.35)^7 and subtract it from . This is the same as at least 1 has </span><span>called a talk show while under the influence of peer pressure
</span><span>1 - (1 - 0.35)^7 = 0.95
</span>
Answer:
Explanation has been given below
Step-by-step explanation:
a) inter arrival times are exponentially distributed with mean 1/n , where n = rate = 1/sec.
probability distribution function is F(t)=n*exp(-n*t).
reference to any kth packet and the (k-1)th packet
the answer is = integration of F(t).dt with limits 0 to 2 = 1 - exp(-2*n) = 1 - exp(-2)
b) t=5 , P(q) = exp(-5)*(5)^q/factorial(q)
probability of fourth call within t=5 seconds is =
that is P(4) P(5) ...... = 1 - ( P(0) P(1) P(2) P(3) ) ; put the values and get the answer.
c) number of calls/rate = 4/n = 4 seconds
Just divide 70 by 2 and you get 35
