Question

Number 76 nunber 77 number 78and 79 please

Answer 1

76) 2n⁴ × 5n⁴ =
$10 {n}^{8}$
77) 5v³ × v⁴ × 7v⁴ =
$35 {v}^{11}$
78) (3n² × 15n³)/5n⁴ = (45n^5)/5n⁴ = 9n
79) (2k⁴)² =
$4{k}^{8}$

I have used the rules stated above these questions, so when multiplying exponents, a¹ × a² = a^(1 + 2), and 2a¹ × 3a² = (2 × 3)a³.
I hope this helps!