Given that two digit numbers are used and one digit is drawn randomly.
Sample space = {10,11,...99}
n(S) = 90
32 is only one number favorable
Hence P(32) = 1/90
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Odd numbers are exactly 45.
Hence prob (odd number) = 45/90 = 1/2
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Multiples of 5 are 10,15,.....95
There are exactly 18 numbers.
Hence P(a multiple of 5) = 18/90 =1/5
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Let x be the amount (the volume in milliliters) of the 5% solution to be mixed.
Then the volume of the 1% solution is 100-x milliliters.
Then your "concentration" equation is
%280.01%2A%28100-x%29+%2B+0.05%2Ax%29%2F100 = 0.02,
or, equivalently,
100-x + 5*x = 200,
which implies
4x = 100 ----> x = 100%2Fx = 25.
Answer: 25 milliliters of the 5% solution must be mised with 100-25 = 75 milliliters of the 1% solution.
First one is 3/8>1/3
Second one is B
Third one is C
Fourth one is B
Answer:
please forgive me I have no clue
Step-by-step explanation:
