Answer:
392 kJ
Explanation:
Given that,
The total mass of the cabin and the passengers = 800 kg
The vertical distance between B and C is 50 m.
We need to find the increase of gravitational potential energy of the cabin and passengers when they move from B to C. It can be given by the relation as follows :
So, the increase in gravitational potential energy is 392 kJ.
Answer:
(A)
(B) s = 146.664 m
Explanation:
We have given car starts from the rest so initial velocity u = 0 m /sec
Final velocity v = 88 km/hr
We know that 1 km = 1000 m
And 1 hour = 3600 sec
So
Time is given t = 12 sec
(A) From first equation of motion v = u+at
So
So acceleration of the car will be
(b) From third equation of motion
So
s = 146.664 m
Distance traveled by the car in this interval will be 146.664 m
These are the matched answers:
Answer:
Assuming the height of the first body is h and the speed of the second one is v, just equate the PE of the first with the KE of the second:
mgh = (1/2) mv^2
since they have equal mass, it cancels out and you can solve for h.
Explanation: