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3 years ago

A car takes 15 minutes to travel along a road that is 20 km long.

Physics

2 answers:

iogann1982 [59]3 years ago

8 0

Answer:

Explanation:

15. 20

x4. x4

60. 80

80km/h

kupik [55]3 years ago

3 0

Answer:

80km/h

Explanation:

solution

given

d=20km

t=15min/60min=0.25h

s=?

s=d/t

s=20km/0.25h

s=80km/h

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An elevator provides 21 000 w of power during a 12 s ride. how much work does the elevator do?

Mice21 [21]

Answer:

252000 J

Explanation:

W = Pt

W = (21000 w)(12 s)

W =252000 J

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2 years ago

Is vapor pressure independent of atmospheric pressure? - This is what my instructor told me, but I don't understand why. ...?

miss Akunina [59]

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3 years ago

A Ground Fault Circuit Interrupter (GFCI) works by comparing the amount of current going to and returning from equipment along t

DanielleElmas [232]

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3 years ago

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A truck initially traveling at a speed of 22 meters per second increases speed at a constant rate of 2.4 meters per second^2 for

Usimov [2.4K]

Thank you for posting your question here. The total distance traveled by the truck during the 3.2 seconds interval is 83 m. Below is the solution:

d = vit + 1/2 at^2
d = (22m/ s) (3.2s) + 1/2 (2.4m/ s^2) (3.2s)^2
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Hope the answer helps.

8 0

3 years ago

mass of the planet is 12 times that of earth and its radius is thrice that of earth , then find the escape velocity on that plan

Over [174]

Answer:

The escape velocity on the planet is approximately 178.976 km/s

Explanation:

The escape velocity for Earth is therefore given as follows

The formula for escape velocity, $v_e$ , for the planet is $v_e = \sqrt{\dfrac{2 \cdot G \cdot m}{r} }$

Where;

$v_e$ = The escape velocity on the planet

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

m = The mass of the planet = 12 × The mass of Earth, $M_E$

r = The radius of the planet = 3 × The radius of Earth, $R_E$

The escape velocity for Earth, $v_e_E$ , is therefore given as follows;

$v_e_E = \sqrt{\dfrac{2 \cdot G \cdot M_E}{R_E} }$

$\therefore v_e = \sqrt{\dfrac{2 \times G \times 12 \times M}{3 \times R} } = \sqrt{\dfrac{2 \times G \times 4 \times M}{R} } = 16 \times \sqrt{\dfrac{2 \times G \times M}{R} } = 16 \times v_e_E$

$v_e$ = 16 × $v_e_E$

Given that the escape velocity for Earth, $v_e_E$ ≈ 11,186 m/s, we have;

The escape velocity on the planet = $v_e$ ≈ 16 × 11,186 ≈ 178976 m/s ≈ 178.976 km/s.

3 0

2 years ago