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Damm [24]
3 years ago
9

A car takes 15 minutes to travel along a road that is 20 km long.

Physics
2 answers:
iogann1982 [59]3 years ago
8 0

Answer:

C

Explanation:

15. 20

x4. x4

60. 80

80km/h

kupik [55]3 years ago
3 0

Answer:

80km/h

Explanation:

<u>solution</u>

given

d=20km

t=15min/60min=0.25h

s=?

s=d/t

s=20km/0.25h

s=80km/h

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A 14n force is applied for 0.33 seconds, calculate the impulse
Shalnov [3]

Answer:

4.62 N-s

Explanation:

recall that the formula for impulse is given by

Impulse = Force x change in time

in our case, we are given

Force = 14 N

change in time = 0.33s

Simply substituting the above into the equation for impulse, we get

Impulse = Force x change in time

Impulse = 14 x 0.33

= 4.62 N-s

5 0
3 years ago
What is the function of the electron transport chain in cellular respiration. why is oxygen needed for the electron transport ch
SpyIntel [72]
1) <span>The function of the electron transport chain is to pump protons in the mitochondrion inter-membrane, thus building up a proton gradient. This gradient will allow the ATP syntheses</span><span>.</span>

2) Why we need oxygen for the electron transport chain:
 At the end of the electron transport chain is the Oxygen that will accept electrons and picks up protons to form water. If the oxygen molecule is not there the electron transport chain will stop running, and ATP will no longer be produced. Basically, we need the oxygen to produce more ATP.


8 0
4 years ago
A catapult launches a test rocket vertically upward from a well, giving the rocket an initial speed of 80.0 m/s at ground level.
BARSIC [14]

Answer:

There is an interval of 24.28s in which the rocket is above the ground.

Explanation:

y_{i}=0m

v_i=80\frac{m}{s}

a=4\frac{m}{s^2}

y_{e}=1000m

g=9.8\frac{m}{s^2}

From Kinematics, the position y as a function of time when the engine still works will be:

y(t)=v_it+\frac{1}{2}at^2

At what time the altitud will be y_{e}=1000m?

v_it+\frac{1}{2}at^2=y_{e} ⇒ \frac{1}{2}at^2+v_it-y_{e}=0

Using the quadratic formula: t_1=10s.

How much time does it take for the rocket to touch the ground? No the function of position is:

y(t)=y_{e}+v_et-\frac{1}{2}gt^2

Where our new initial position is y_{max}, the velocity when the engine breaks is v_e=v_i+at=120\frac{m}{s} and the only acceleration comes from gravity (which points down).

Now, when the rocket tounches the ground:

y_{e}+v_et-\frac{1}{2}gt^2=0

Again, using the quadratic ecuation:

t_2=24.49s

Now, the total time from the moment it takes off and the moment it tounches the ground will be:

t_T=t_1+t_2=34.49s.

6 0
4 years ago
Why is Pluto considered less of an oddball planet now?
solmaris [256]

Answer:

The International Astronomical Union (IAU) downgraded the status of Pluto to that of a dwarf planet because it did not meet the three criteria the IAU uses to define a full-sized planet. Essentially Pluto meets all the criteria except one—it “has not cleared its neighboring region of other objects

Explanation:

4 0
3 years ago
1 - A submarine has a circular porthole with a radius of 0.10 m. If a force of more than 2x106 N is applied, the porthole will f
S_A_V [24]

In order to solve this problem, it is necessary to apply the concepts related to the Pressure according to the Force and the Area as well as to the pressure depending on the density, gravity and height.

In the first instance we know that the pressure can be defined as

P = \frac{F}{A}

Where

F= Force

A =  Mass

In the second instance the pressure can also be defined as

P = \rho gh

Where,

\rho=Density of Fluid at this case Water

g = Gravitational Acceleration

h = Height

If we develop the problem to find the pressure then,

P = \frac{F}{A}

P = \frac{F}{\pi r^2}

P = \frac{2*10^6}{\pi (0.1)^2}

P = 6.37*10^{7} Pa

Through the second equation we can find the depth to which it can be submerged,

P = \rho gh

Re-arrange to find h

h = \frac{P}{\rho g}

h = \frac{6.37*10^{7}}{1000*9.8}

h = 6499.4m

8 0
3 years ago
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