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Oksi-84 [34.3K]
3 years ago
7

Find the perimeter and area of length 3cm and width 5 cm

Mathematics
1 answer:
Anni [7]3 years ago
4 0
L = 5 and w = 3

Perimeter = 2(l + w)
P = 2(5 + 3)
P = 2(8)
P = 16 cm


Area = l*w
Area = 5*3
Area = 15 cm^2
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Step-by-step explanation:

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3 years ago
a rectangular box with two sqaure opposite ends is to hold 8000 cubic inches. find the dimensions of the cheapest box if tge rec
AveGali [126]

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since the box has a volume V

V= x*y*z = b=8000 in³

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V= x*y² = b=8000 in³

and the cost function is

cost = cost of the square faces *  area of square faces + cost of top and bottom * top and bottom areas + cost of the rectangular sides * area of the rectangular sides

C = a* 2*y² +  a* 2*x*y + 15*a* 2*x*y =  2*a* y² +  32*a*x*y

to find the optimum we can use Lagrange multipliers , then we have 3  simultaneous equations:

x*y*z = b

Cx - λ*Vx = 0 → 32*a*y -  λ*y² = 0 → y*( 32*a-λ*y) = 0 → y=32*a/λ

Cy - λ*Vy = 0  → (4*a*y + 32*a*x) - λ*2*x*y = 0

4*a*32/λ  + 32*a*x - λ*2*x*32*a/λ = 0

128*a² /λ +  32*a*x - 64*a*x = 0

32*a*x = 128*a² /λ

x  = 4*a/λ

x*y² = b

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then

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then the box has dimensions 5 in x 40 in x 40 in

3 0
3 years ago
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