43 times 68.
43
x68
8 times 3 is 24. Bring the 2 over the 4.
8 times 4 is 32. Add 4. Equals 36.
Answer so far is 364.
Add a 0 before answering.
3 times 6 is 18. Bring the 1 over the 4.
4 times 6 is 24. Add 4. Equals 28.
Answer so far is 288
Add 364 + 288
Final answer is 652.
Answer:
the cost of running the boarding
house for 600 students is N61,000
Step-by-step explanation:
Let C represents cost
K1 represents first constant
K2 represents second constant
C= k1+k2n
3500 = k1 + 25 k2............. Eqn(1)
6000= k1 + 50 k2 .............. Eqn(2)
Subtract eqn(1) from eqn(2)
2500= 25k2
K2= 2500/25
K2= 100
To get k1 from eqn(1)
3500 = k1 + 25 k2
Substitute the value of k2
3500 = k1 + 25 (100)
3500= k1 +2500
K1= 3500- 2500
K1= 1000
The equation connecting them;
C= 1000+ 100n
The cost of running the boarding
house for 600 students is
n= 600
C= 1000+ 100(600)
C= 1000+60000
C= N 61,0000
Okay, to find length CE, your going to know the value of x. Length BC + CE = BD + DE.3x+47+x+26=27+x+10Simplify the equation to get4x+73=37+xyou can choose one of four ways to continue, but I will choose to subtract x3x+73=37Subtract 73 from both sides of the equal sign3x=-36divide by 3 on both sides of the equal sign to get the value of xx=-12Now, plug in -12 for x in length CE to get -12+26=14
111,000 because you do 30000+32000+49000.
