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Nonamiya [84]
3 years ago
10

-11 2/3 * (-4 1/5) = ? Will try to mark brainliest please hurry

Mathematics
2 answers:
Trava [24]3 years ago
6 0
Answer is 49
Pls mark me brainliest
Elenna [48]3 years ago
3 0

Answer:

306.13

Step-by-step explanation:

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Please answer!it is grade 6 math
vova2212 [387]
Answer:

AB+BE+EF+GF+HG+AH = 14 #EQU 1
BC+CD+DE+EF+GF+BG = 22 #EQU 2
AB+BC+CD+DE+EF+GF+HG+AH = 24 #EQU 3
IMPLEMENTING EQU 2 IN EQU 3
AB+22-EF+ HG+AH = 24 # EQU 5
FROM EQU 1
AB+HG+AH = 14-(BE+EF+GF) #EQU 4
IMPLEMENTING EQU 4 IN EQU 5
22+14 - (BE+EF+GF+EF) = 24
36 - 24 = BE+EF+GF+BG(EF=BG)
12 = PATH TAKEN ON THURSDAY

5 0
2 years ago
What is the equation of the graph ?
mezya [45]
5 over and 4 ^. not sure if this is correct but that’s what i got
8 0
3 years ago
Philip is conducting a survey to determine the weight of 100 cows on a farm. Which of the following questions is an appropriate
liubo4ka [24]
Because Philip is conducting a survey that pertains to the weight of the cows, he needs statistics that directly relate to weight.

The cows being overweight doesn't give Philip concrete information on the weight of the cows, as it doesn't give the amount of pounds a cow weighs. Average age has nothing to do with weight, and normal body weight doesn't give concrete information on weight.

The answer is "<span>What is the weight of each cow on the farm?".</span>
5 0
3 years ago
Read 2 more answers
Suppose that scores on an aptitude test are normally distributed with a mean of 100 and a standard deviation of 4.6. Scores on a
DerKrebs [107]

Answer:

<u>The correct answer is C. Felix's z-score on the aptitude test was 1.30. His z-score on the knowledge test was 2.08. Felix performed better on the knowledge test, comparatively.</u>

Step-by-step explanation:

1. Let's check all the information given to us to answer the question correctly:

Mean of the scores on the aptitude test = 100

Standard deviation of the aptitude test = 4.6

Felix's score on the aptitude test = 106

Mean of the scores on the knowledge test = 70

Standard deviation of the knowledge test = 2.4

Felix's score on the knowledge test = 75

2. Which statement best describes Felix's scores on the two tests comparatively?

Let's recall that z-score in a normal distribution, positive or negative, is the number of times of the standard deviation a certain element is from the mean. If the element is below the mean, then the z-score is negative and if it's above the mean, then the z-score is positive.

Therefore, a score of 106 on the aptitude test, will have the following z-score:

106 - 100 = 6 and it's above the mean.

Now, we calculate the z-score, using the value of the standard deviation this way:

6/4.6 = 1.30

A score of 75 on the knowledge test, will have the following z-score:

75 - 70 = 5 and it's above the mean.

Now, we calculate the z-score, using the value of the standard deviation this way:

5/2.4 = 2.08

The z-scores of Felix were 1.30 on the aptitude test and 2.08 on the knowledge test. He performed better on the aptitude test because 2.08 > 1.30, so the correct statement that best describes Felix's scores on the two tests comparatively is<u> C. Felix's z-score on the aptitude test was 1.30. His z-score on the knowledge test was 2.08. Felix performed better on the knowledge test, comparatively.</u>

6 0
3 years ago
CAN SOME1 PLEASEE THINK OF AN EQUATION AND SOLVE IT FOR ME?
KatRina [158]
A example can be Keith has $500 in a savings account at the beginning of the summer. He wants to have at least $200 in the account by the end of the summer. He withdraws $25 each week for food, clothes, and movie tickets. The answer would be Any more than 12 weeks and his account balance would be less than $200. Any number of weeks less than 12 and his account would stay above $200.
8 0
3 years ago
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