The question is asking what v_final is, given that v_initial is at 300 feet. and v_initial is at 0 feet.
We know there will be a constant downward acceleration of 32.15 ft/s^2.
Use the following equation:
v_final^2 = v_initial^2 + 2ah
v_final^2 = (160 ft/s)^2 + 2(-32.15 ft/s^2)(300 ft) = 6310 ft^2/s^2
v_final = (6310 ft^2/s^2)^1/2 = 79.4 ft/s.
The answer would be B because range is the highest number take away the lowest number
Answer:
I/rt =P
Step-by-step explanation:
to get ride of the r and t u need to divide
divide by rt
which would =to I/rt=P
Answer:
thanks i guess
Step-by-step explanation:
15.4m Square because That is what I got when I times those two together
