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erica [24]
3 years ago
6

If there are 20 beers bottles and chad drank 5. Kyle drank 10 how many beers would there be left???

Mathematics
2 answers:
zavuch27 [327]3 years ago
6 0

Answer:

5

Step-by-step explanation:

20-15= 5

Ad libitum [116K]3 years ago
5 0
5 would be left its pretty easy my g
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A 20 foot extension ladder liens against a building if the base of the latter is placed 6 feet from the base of the building wha
goldenfox [79]

For this problem, you're going to need to use trig. More specifically, you need to use the tangent function:

tan (value) = opposite/adjacent

tan 75 = opposite/8 (Here, the opposite side is the length of the ladder)

8 * tan 75 = opposite

29.8564065 = opposite

So, the ladder is 29.9 feet.

6 0
3 years ago
If b is the midpoint of AC, which of the following choices is the value of x?
katrin [286]
If B is the midpoint of AC, that means that the distances from A to B and B to C are the same. The distance from A to B is 8x + 4, and the distance from B to C is 10x - 6, so we can set these two equivalent:

8x + 4 = 10x - 6

Solving for x:

4 = 2x - 6 (subtract 8x from both sides)
10 = 2x (add 6 to both sides)
5 = x (divide both sides by 2)

So, x = 5, which is the second option given.
8 0
3 years ago
A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters
In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

\Rightarrow y=\sqrt{x^2+100}

Differentiating with respect to t

\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}

\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}

Since the car driving towards the intersection at 13 m/s.

so,\frac{dx}{dt}=-13

\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)

Now

\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)

               =\frac{24\times (-13)}{\sqrt{676}}

               =\frac{24\times (-13)}{26}

               = -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0
3 years ago
Solve for x<br> 6.58-8.36x=3.98x-27.33<br> Round to nearest hundred
ololo11 [35]

Answer:

6.58-8.36x=3.98x-27.33

Collecting like terms

6.58+27.33=3.98x+8.36x

33.91=12.34x

33.91/12.34=12.34/12.34

x=2.75

7 0
3 years ago
Read 2 more answers
Arianna runs up 4 flights of stairs then runs down 4 flights of stairs. Does this situation represent additive inverses
dexar [7]

Answer:

Yes because she ends up back at zero

8 0
3 years ago
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