Answer:
The standard form of the equation for this line can be:
l: 2x + 5y = -15.
Step-by-step explanation:
Start by finding the slope of this line.
For a line that goes through the two points 
and 
,
.
For this line,
.
Find the slope-point form of this line's equation using
, and- The point
(using the point 
should also work.)
The slope-point form of the equation of a line
- with slope
and - point
should be 
.
For this line,
The equation in slope-point form will be
.
The standard form of the equation of a line in a cartesian plane is
where
, 
, and 
are integers. 
.
Multiply both sides of the slope-point form equation of this line by 
:
.
Add 
to both sides of the equation:
.
Therefore, the equation of this line in standard form is .
Answer:
10
Step-by-step explanation:
Ground level is where h = 0, so solve the equation ...
h(x) = 0
-5(x -4)^2 +180 = 0 . . . . substitute for h(x)
(x -4)^2 = 36 . . . . . . . . . . divide by -5, add 36
x -4 = 6 . . . . . . . . . . . . . . positive square root*
x = 10 . . . . . . add 4
The object will hit the ground 10 seconds after launch.
_____
* The negative square root also gives an answer that satisfies the equation, but is not in the practical domain. That answer would be x = -2. The equation is only useful for time at and after the launch time: x ≥ 0.
then find y and plug that y value into one of the original equations to find x
Hope this helps!
Is there more to this question?
Answer:
The answer is c!
Step-by-step explanation:
, and
, and
.
