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3 years ago

Help please ... thanks

Mathematics

2 answers:

lapo4ka [179]3 years ago

5 0

Put the equation in desmos and you will get your answer :)

dedylja [7]3 years ago

3 0

Start at point (0,-6) or start at the point that’s -6 on the y line. Then count up 9 the 1 to the right a place a point there. Finally connected ur two lines and that’s the line for your equation

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The attached image has the question; thank you for helping. Please have a step-by-step explanation; thank you.

nika2105 [10]

The area of the right angled triangle is 8 cm^2.

According the statement

we have to find the area of the right angled triangle with the help of the given equation.

So, For this purpose, we know that the

A right-angled triangle is a type of triangle that has one of its angles equal to 90 degrees. The other two angles sum up to 90 degrees.

From the given information:

The length of the perpendicular side (call as a) = 2cm

And

The length of the base side (call as b) = 8cm

We know that the area of the right angle triangle is :

Area = ab /2

Then

substitute the terms in it then

Area = 2*8/2

Area = 8 cm^2.

So, The area of the right angled triangle is 8 cm^2.

Learn more about right angled triangle here

brainly.com/question/64787

#SPJ1

4 0

2 years ago

A population has a mean muequals160 and a standard deviation sigmaequals20. Find the mean and standard deviation of the sampling

hoa [83]

Answer:

Mean 160

Standard deviation 2.63

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n of at least 30 can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 160, \sigma = 20$

Find the mean and standard deviation of the sampling distribution of sample means with sample size n = 58.

Mean 160

Standard deviation $s = \frac{20}{\sqrt{58}} = 2.63$

6 0

4 years ago

which set of side lengths form a right side?a) 3ft,6ft,5ft b)50 in,48in,14in c)53m,48m,24m d)8cm,17cm,14cm

muminat

Answer:

Step-by-step explanation:

If a ≤ b < c form of a right side, then a² + b² = c²

a) 3ft, 6ft, 5ft

3² + 5² = 6²

9 + 25 = 36

34 = 36 FALSE

b) 50in, 48in, 14in

14² + 48² = 50²

196 + 2304 = 2500

2500 = 2500 CORRECT :)

c) 53m, 48m, 24m

24² + 48² = 53²

576 + 2304 = 2809

2880 = 2809 FALSE

d) 8cm, 17cm, 14cm

8² + 14² = 17²

64 + 196 = 289

260 = 289 FALSE

3 0

3 years ago

Read 2 more answers

If one root of the equation is 4x^2- 2x+p-4 be the reciprocal of other. then find the value of p

SashulF [63]

Answer:

p = 8

Step-by-step explanation:

Let one root of the eqn. be alpha . Other root is 1/alpha .

We know that product of both roots of an quadratic eqn. is c/a where "c" is the co-efficient of the constant & "a" is the co-efficient of x^2.

Here "c" is p-4 & "a" is 4. And the product of roots is 1 ( ∵ prdouct of a number and its reciprocal is 1 )

$\frac{c}{a} = 1\\=> \frac{p - 4}{4} = 1\\=> p - 4 = 4\\=> p = 4 + 4 = 8$

5 0

4 years ago

Solve (2/3)-(1/x)=5/6

Keith_Richards [23]

$\frac{2}{3} - \frac{1}{x} = \frac{5}{6}$ Multiply both sides by 3
$2 - \frac{1(3)}{x} = \frac{5(3)}{6}$ Simplify the numerators
$2 - \frac{3}{x} = \frac{15}{6}$ Multiply both sides by 6
$12 - \frac{3(6)}{x} = 15$ Simplify the numerator
$12 - \frac{18}{x} = 15$ Multiply both sides by x
12x - 18 = 15x Subtract 12x from both sides
-18 = 3x Divide both sides by 3
-6 = x Switch the sides to make it easier to read
x = -6

Check your answer by plugging -6 in for the x in the original problem:

$\frac{2}{3} - \frac{1}{x} = \frac{5}{6}$ Plug in -6 for x
$\frac{2}{3} - \frac{1}{-6} = \frac{5}{6}$ Change $\frac{2}{3}$ to $\frac{4}{6}$ so all denominators are the same
$\frac{4}{6} - \frac{1}{-6} = \frac{5}{6}$ Change $\frac{1}{-6}$ to $\frac{-1}{6}$ for easier work
$\frac{4}{6} - \frac{-1}{6} = \frac{5}{6}$ Subtract the numerators (4 - (-1) )
$\frac{5}{6}$ = $\frac{5}{6}$

So, x = -6 .

5 0

3 years ago