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IgorLugansk [536]

3 years ago

11

A 12 foot ladder is leaning against a building . The ladder makes a 45 degree angle with the building . How far up the building

does the ladder reach ?

2 answers:

Firlakuza [10]3 years ago

8 0

May this method work

Mark as brainliest give 5 star

Evgesh-ka [11]3 years ago

4 0

Answer:

the answer on apex is 6 sqrt 2...... i just did it

Step-by-step explanation:

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A regular hexagon is inscribed in a circle as shown determine the measure of FE

Ostrovityanka [42]

The complete question in the attached figure

we know that
1) <span>The triangles that are formed in the hexagon by joining all the vertices with the center of the hexagon are all equilateral and are equal in size
therefore
the radius of the circle is equals to the length side of the regular hexagon
FE=BP--------> FE=6 cm

the answer is
FE=6 cm </span>

3 0

3 years ago

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What is the square root of 108 in simplified radical form?

Alenkinab [10]

$\sqrt{108}=\sqrt{36 \times 3}=\sqrt{36} \times \sqrt{3}=6 \times \sqrt{3}=\boxed{6\sqrt{3}}$

5 0

3 years ago

Please show your work!!

jarptica [38.1K]

Answer:OK ILL HELP

Step-by-step explanation:Combine

1

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6 0

3 years ago

The measure of an inscribed circle of an angle is the measure of the intercepted arc

Andre45 [30]

Answer:

(the statement does not appear to be true)

Step-by-step explanation:

I don't think the statement is true, but you CAN compute the intercepted arc from the angle.

Note that BFDG is a convex quadrilateral, so its angles sum to 360. Since we know the inscribed circle touches the angle tangentially, angles BFD and BGD are both right angles, with a measure of 90 degrees.

Therefore, adding the angles together, we have:

alpha + 90 + 90 + <FDG = 360

Therefore, <FDG, the inscribed angle, is 180-alpha (ie, supplementary to alpha)

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3 years ago

E=mc2 Solve for C<br><br> Can someone help me solve for C?

zepelin [54]

C = sqrt(e/m)

You can get this by first dividing away the m and then taking the square root of both sides.

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3 years ago

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