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statuscvo [17]
4 years ago
6

Simplify three to the negative ninth divided by three to the negative twelfth in decimal form.

Mathematics
1 answer:
inysia [295]4 years ago
6 0
The answe is 3 to the third or 27
You might be interested in
A
Gnesinka [82]

Answer:

A: 779 cm²

B: 1837 cm²

Step-by-step explanation:

For both problems, use the formula for surface area of a cylinder:

SA = 2πr² + 2πrh

2πr² is the two bases.

2πrh is the curved surface.

<u>PROBLEM A</u>

"the cylinder is 60 cm long" is h = 60.

If given diameter, you can find "r" by dividing it by 2. d = 2r

Given d = 4, then r = 2.

SA = 2πr² + 2πrh

SA = 2π2² + 2π2(60)

SA = 8π + 240π               Add

SA = 248π                       Exact answer

SA ≈ 779.114978             Answer on calculator

SA ≈ 779           Rounded answer

Remember to include the units.

The surface area is about 779 cm².

<u>PROBLEM B</u>

"80 cm long" h = 80.

"circumference of 22 cm". C = 22. Remember C = 2πr. Find "r".

C = 2πr

22 = 2πr

11 = πr

r ≈ 11/π

SA = 2πr² + 2πrh

SA = 2π(11/π)² + 22(80)       Substitute 2πr with the circumference.

SA ≈ 1837.030992            Answer on calculator

SA ≈ 1837               Rounded answer

Remember to include the units.

The surface area is about 1837 cm².

7 0
4 years ago
-0.5 x 1/3 estimate each product or quotient and then compute
Gnoma [55]
 -0.5 * 0.3 =  - 0.15 .
______________________________________
7 0
3 years ago
Does anyone understand and can help me asap?
nydimaria [60]

Answer:

see below

Step-by-step explanation:

Circumference of circle = 2πr =dπ

Area of circle =πr²

1) Circle1 d =4 in, r =2 in

Circumference of circle1 =4π in

Area of circle1 = 2²π =4π in²

2) Circle2: d =3 in, r =1.5 in

Circumference of circle2 =3π in

Area of circle2 = 1.5²π =2.25π in²

3)  Circle3:  r =1 in, d =2 in

Circumference of circle3 =2π in

Area of circle3 = 1²π =π in²

4) Circle4:  r =2 1/2 in = 2.5 in, d =5 in

Circumference of circle4 =5π in

Area of circle4 = 2.5²π = 6.25π in²

5) 2/3 of the Area of circle1 = (2/3)*4π in²= (8/3)π in²

6) 1/2  of the Area of circle2 = (1/2)*2.25π in² = (1/2)*(9/4)π in² = (9/8)π in²

7) 1/4  of the Area of circle3 = (1/4)π in²

8) 1/3  of the Area of circle4 = (1/3)* 6.25π in² =(1/3)*(25/4)π in² = (25/12)π in²

6 0
3 years ago
If you wanted to draw the trend line for the given scatter plot, you would what.
irina [24]
Trendline is drawn over the data points of the scatter plot in order to project which way the plot is directed. If we want to draw the trend line, we should consider the points that will best represent the data. Therefore, the answer to this item is letter C. 
3 0
4 years ago
Read 2 more answers
Evaluate the expression. 3(√27−16)
Anvisha [2.4K]

Step-by-step explanation:

step 1. 3(sqr(27) - 16) sqr is the square root

step 2. 3(3sqr3 -16)

step 3. 9sqr3 - 48.

8 0
3 years ago
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