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Vinvika [58]
2 years ago
5

Given: Circle k (O), OA and OC -radii, AP and CP - tangents, m∠AOC=150° Find: m∠APC

Mathematics
1 answer:
viva [34]2 years ago
3 0

Answer:

m∠APC = 30°

Step-by-step explanation:

To solve for the above question, we would be making use of circle theorems

Looking at the circle, we can see that

m∠APC is an Angle outside the circle

m∠AOC is a smaller arc in the circle.

Therefore, Circle Theorem states that for a circle with two tangents,

The Angle outside the circle + The smaller arc = 180°

Hence,

m∠AOC + m∠APC = 180°

m∠APC = 180° - m∠AOC

m∠APC = 180° - 150°

m∠APC = 30°

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For finding side a, you can answer this easily by the Law of Cosines. The equation is

a2=b2 +c2 -2bccosA
a2 = 11^2 + 8^2 -2(11)(8)(cos54)
a2 = 81.55
a = √81.55
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Then, we use the Law of Sines to find angles B and C. The formula would be

a/sinA = b/sinB = c/sinC
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A building engineer analyzes a concrete column with a circular cross section. The circumference of the column is 18π meters.
Whitepunk [10]

Answer:

A=81\pi\ m^{2}

Step-by-step explanation:

Step 1

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we know that

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substitute and solve for r

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simplify

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Step 2

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r=9\ m

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A=\pi (9)^{2}

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8 0
3 years ago
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photoshop1234 [79]
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