In this problem, you apply principles in trigonometry. Since it is not mentioned, you will not assume that the triangle is a special triangle such as the right triangle. Hence, you cannot use Pythagorean formulas. The only equations you can use is the Law of Sines and Law of Cosines.
For finding side a, you can answer this easily by the Law of Cosines. The equation is
a2=b2 +c2 -2bccosA
a2 = 11^2 + 8^2 -2(11)(8)(cos54)
a2 = 81.55
a = √81.55
a = 9
Then, we use the Law of Sines to find angles B and C. The formula would be
a/sinA = b/sinB = c/sinC
9/sin54° = 11/sinB
B = 80.4°
9/sin54° = 8/sinC
C = 45.6°
The answer would be: a ≈ 9, C ≈ 45.6, B ≈ 80.4
theta is in the fourth quadrant where the cosine is positive.
the third side in the triangle = sqrt (4 - 2) = sqrt2
So sin theta = -sqrt2/2 = Second choice (negative because sine is negative in 4th quadrant)
tan theta = - sqrt2 / sqrt2 = -1
72*12 = 2*2*2*2*2*3*3*3 = 2^5*3^3
Answer:

Step-by-step explanation:
Step 1
Find the radius of the circular cross section
we know that
The circumference is equal to

we have

substitute and solve for r

simplify


Step 2
Find the area of the circular cross section
The area of the circle is equal to

we have

substitute


2/3 is the answer.
<span>1/3 is equal to 33.33333333% </span>
<span>so 2/3 is equal to 66.6666666%</span>