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sdas [7]
3 years ago
8

Two numbers are in the ratio 4: 5

Mathematics
1 answer:
Mkey [24]3 years ago
4 0

Answer:

48 and 75

Step-by-step explanation:

Given data

We are given that the ratio is 4:5

we have two numbers, the bigger and the smaller number

case one: bigger= 60

the smaller is

4/5= x/60

5x= 60*4

5x= 240

x= 48

case two: smaller number = 60

4/5=60/x

4x= 60*5

4x= 300

x= 300/4

x= 75

Hence the two possible numbers are 48 and 75

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If sin A = 3/8, find the value of cosec A - sec A.​
alexira [117]

Answer:

\csc A - \sec A = \dfrac 83 + \dfrac{8}{\sqrt{55}}\\\\\csc A - \sec A = \dfrac 83 - \dfrac{8}{\sqrt{55}}

Step by step explanation:

\text{Given that,}\\\\~~~~~~\sin A = \dfrac 38 \\\\\implies \sin^2 A = \dfrac 9{64}\\\\\implies  1 - \cos^2 A = \dfrac{9}{64}\\\\\implies \cos ^2 A = 1 - \dfrac 9{64}\\\\\implies \cos^2 A = \dfrac{55}{64}\\\\\implies \cos A =\pm\sqrt{\dfrac{55}{64}}\\ \\\implies \cos A = \pm\dfrac{\sqrt{55}}8\\\\

\implies \dfrac 1{\cos A} = \pm\dfrac{8}{\sqrt{55}}

\text{Now,}\\\\\csc A - \sec A\\\\=\dfrac{1}{\sin A}- \dfrac{1}{\cos A}\\\\=\dfrac 83 -\left(\pm \dfrac 8{\sqrt {55}} \right)\\ \\\text{Hence,}\\\\\csc A - \sec A = \dfrac 83 + \dfrac{8}{\sqrt{55}}\\\\\csc A - \sec A = \dfrac 83 - \dfrac{8}{\sqrt{55}}

6 0
2 years ago
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Gekata [30.6K]

Answer:

The answer is -2c - 4w

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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