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2 years ago

Can someone help me please

Mathematics

2 answers:

antoniya [11.8K]2 years ago

6 0

Answer:

From the Information provided by the graph shown above, i can conclude that Berlin's location on the graph is (6,7)

tatuchka [14]2 years ago

4 0

OK the answer is (6,7). THis is true because you always put the x coordinate first and then the y coordinate and the x axis is horizontal and the y axis is vertical.

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what is the slope and equation of a line that is perpendicular to the y-axis passing through (-5,-3)?

Illusion [34]

Answer:

Slope is m=0

$y=-3$

Step-by-step explanation:

The slope of any line that is perpendicular to the y-axis is zero.

The reason is that any line that is perpendicular to the y-axis is also parallel to the x-axis and the slope of the x-axis is zero.

The equation of any line perpendicular to the y-axis is and passes through (a,b) is y=b.

The given point is (-5,-3) hence the required equation is

$y=-3$

3 0

2 years ago

Can someone please help me?

zubka84 [21]

Answer: g is 6 and f is 4

6 0

3 years ago

Convert 11.42424242 … to a rational expression in the form of , where b ≠ 0.

statuscvo [17]

I think it is the second one but im not for sure

I hope that helped you

4 0

3 years ago

GREYUIT [131]

Answer:

$175\ in^{2}$

Step-by-step explanation:

step 1

Find the scale factor

we know that

If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube

Let

z----> the scale factor

x----> volume of the larger solid

y----> volume of the smaller solid

$z^{3}=\frac{x}{y}$

we have

$x=125\ in^{3}$

$y=27\ in^{3}$

substitute

$z^{3}=\frac{125}{27}$

$z=\frac{5}{3}$

step 2

Find the surface area of the larger solid

we know that

If two figures are similar, then the ratio of its surface areas is equal to the scale factor squared

Let

z----> the scale factor

x----> surface area of the larger solid

y----> surface area of the smaller solid

$z^{2}=\frac{x}{y}$

we have

$z=\frac{5}{3}$

$y=63\ in^{2}$

substitute

$(\frac{5}{3})^{2}=\frac{x}{63}$

$x=\frac{25}{9}*63=175\ in^{2}$

3 0

3 years ago

What is the approximate volume of one refraction cup? What’s its formula ?

Marizza181 [45]

Answer:

Volume = 0.1696 L

The formula is Area of base of refraction cup × Depth of the refraction cup

Step-by-step explanation:

The dimensions of a refraction cup are;

Diameter = 120 mm

Depth = 30 mm

Therefore, volume of the refraction cup = Area of base × Depth

Volume of the refraction cup = (π×120²/4)/2 × 30 = 169646.003 mm³

1 L = 1000000 mm³

Therefore, 169646.003 mm³ = 169646.003/1000000 m³ = 0.1696 L

The formula is Area of base of refraction cup × Depth of the refraction cup.

6 0

2 years ago