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3 years ago

Can someone help me please

Mathematics

2 answers:

antoniya [11.8K]3 years ago

6 0

Answer:

From the Information provided by the graph shown above, i can conclude that Berlin's location on the graph is (6,7)

tatuchka [14]3 years ago

4 0

OK the answer is (6,7). THis is true because you always put the x coordinate first and then the y coordinate and the x axis is horizontal and the y axis is vertical.

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The box plots below show student grades on the most recent exam compared to overall grades in the class

DaniilM [7]

Answer:

3. The class median is lower than the exam median

Step-by-step explanation:

The median of the box plot is indicated by the vertical line that divides the box.

Thus, the Class median grade is about 80, while the Exam median grade is more than 80.

Comparing grades, this means that the class median is lower. than the exam median.

Therefore, "the class median is lower than the exam median" is the right information that describes the median.

5 0

3 years ago

What is 19/20 as a terminating decimal

natka813 [3]

$\frac{19}{20} = 0.95$

3 0

3 years ago

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0.05 is 1/10 the value of

Dominik [7]

0.5, 0.05 is 1/10 the value of 0.5

7 0

3 years ago

Solve for m: 8(m+5)=16 ?

Alika [10]

8(m+5)=16
8m+40=16
8m=24
m=3

8 0

3 years ago

Read 2 more answers

What two numbers add up to 6 and multiply to 12?

GuDViN [60]

Erm

x+y=6
xy=12

x+y=6
y=6-x
sub back

xy=12
x(6-x)=12
6x-x^2=12
x^2-6x=-12
x^2-6x+12=0
quadratic formula
for
ax²+bx+c=0
$x= \frac{-b+/- \sqrt{b^2-4ac} }{2a}$

for
x²-6x+12=0
a=1
b=-6
c=12
and remember that √-1=i

$x= \frac{-(-6)+/- \sqrt{(-6)^2-4(1)(12)} }{2(1)}$
$x= \frac{6+/- \sqrt{36-48} }{2}$
$x= \frac{6+/- \sqrt{-12} }{2}$
$x= \frac{6+/- (\sqrt{-1})(\sqrt{12}) }{2}$
$x= \frac{6+/- (i)(2\sqrt{3}) }{2}$
$x= \frac{6+/- 2i\sqrt{3} }{2}$
x=3+/-i√3

the numbers are 3+i√3 and 3-i√3
no real numbers tho

7 0

4 years ago