Answer by BlueSky06
The equation described above can also be written as, y = -x² + 100x + 4000To get the number of notebooks that will give them the maximum profit, we derive the equation and equate to zero. dy/dx = -2x + 100 = 0The value of x from the equation is 50. Then, we substitute 50 to the original equation to get the profit. y = -(50^2) + 100(50) + 4000 = 6500Thus, the maximum profit that the company makes is $6,500/day.
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Answer:
The test statistics is 
Step-by-step explanation:
From the question we are told that
The data given is
330 620 1870 2410 4620 6396 7822 81028309 12882 14419 16092 18384 20916 23812 25814
The population mean is 
The sample size is n = 16
The null hypothesis is 
The alternative hypothesis is 
The sample mean is mathematically evaluated as

So

=> 
The standard deviation is mathematically represented as

So



=> 
Generally the test statistic is mathematically represented as


From the z-table the p-value is

From the values obtained we see that
so we fail to reject the null hypothesis
Which implies that the claim of the NarStor is wrong
Both a and b are functions. for it to be a function, you can only have 1 y value per x value.
this is not a function because 1 has 2 y values
(1,3)(2,5)(1,4)(3,2)
Answer:
u33u3373737
Step-by-step explanation:
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Answer:6
Step-by-step explanation: