3.) 3, 4, 5
&
4.) 6, 8, 10
Those two are right triangles because when you add the squares of the first two it should give you the square root of the third number
a^2 + b^2 = c^2
So
3^2 + 4^2 = 5^2
9 + 16 = 25
25 = 25
6^2 + 8^2 = 10^2
36 + 64 = 100
100 = 100
Therefore they are right triangles
But 1 & 2 aren’t right triangles because when you add the squares of the first two number, it doesn’t equal to the square root of the third number.
Hope this helps!!
Answer:
and 
Step-by-step explanation:
A simple way to solve this problem is to plug the corresponding x and y into the function. We need only one pair since all the functions are quasi-linear (y=kx) and the increase is proportional.
In when x=3, y=15/4≈2.14
In 
when x=3, y=1.8
In when x=3, y≈2.33
In 
when x=3, y≈1.90
We can observe that in two cases, and , y is greater than 2.
Answer:
y = -51 ÷ x
Step-by-step explanation:
The standard format of a inversely proportional equation goes by the format of y = k ÷ x. The question asks us to write an equation if y = -3 when x = 17 and y varies inversely with x.
So we substitute the values y = -3 and x = 17 in the equation y = k ÷ x
K = constant, we have to work this out
-3 = k ÷ 17
-3 × 17 = k
k = -3 × 17
k = -51
k = -51 So then we put this back into the original y = k ÷ x to find our final equation which is y = -51 ÷ x
Step-by-step explanation:
(
2
x
)
2
−
3
2
=
(
2
x
−
3
)
(
2
x
+
3
)
