Question

The time a basketball player spends in the air when shooting a basket is called the​ "hang time." the vertical leap l measured in feet is related to the hang time t measured in seconds by the equation lequals=4 t squared4t2. suppose that a basketball player has a vertical leap of 33 feet 44 inches. find the hang time for this leap.

Answer 1

Dénote l the vertical leap, then the given equation can be written like this:
$l(t)=4t^2\\\text{Since one inch equate 0.0833333 feet then 44 inches equate }\\44\times 0.0833333=3.6feet\\\text{Add to 33 feet like this:}\\33+3.6=36.6feet\\\text{Now we have to solve the equation:}\\4t^2=36.6\\\text{Divide over 4 we get:}\\t^2= \frac{36.6}{4}=9.15\\\text{Take the square root we get:}\\t=\sqrt{9.15}=3$

The hang time equates then 3 seconds