Sample Response: The object will hit the ground after 5 seconds. You can rewrite the quadratic function as a quadratic equation set equal to zero to find the zeros of the function 0 = –16t2 + 80t + 0. You can factor or use the quadratic formula to get t = 0 and t = 5. Therefore, it is on the ground at t = 0 (time of launch) and then hits the ground at t = 5 seconds
What did you include in your response? Check all that apply.
I Rewrite the quadratic function as a quadratic equation set equal to zero: 0 = –16t2 + 80t + 0.
Use the quadratic formula to solve for the zeros.
Factor to solve for the zeros.
t = 0 and t = 5 seconds.
The object will hit the ground after 5 seconds.
Answer:
A=5/2a^2(5+2√5)
Step-by-step explanation:
When you write it as an inequality you get x + 4 > 13
Answer:
Well none of the answers are correct as maximum height is found by doing -b/2a which gives the x coordinate of the vertex also known as the heighest or lowest point. But when plugged in it gives the lowest point assuming you made the mistake of making the 16 positive when its supposed to be negative you would plug it in and get 98 which isn't an answer choice assuming 34 is the ground when you subtract that you get 64 whch still isn't an answer choice check your numbers in the equation