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2 years ago

9x + 3 – 7x + 4 Help me out please?

Mathematics

2 answers:

SOVA2 [1]2 years ago

8 0

Answer: The answer is 2x + 7.

Explanation: First, we need to add the numbers:

9x + 3 – 7x + 4

9x + 7 - 7x

And finally, we combine like terms:

9x + 7 - 7x

2x + 7

andreev551 [17]2 years ago

6 0

The answer is 2x plus 7

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I need help and the answer is?

frozen [14]

Answer:

0.002

Step-by-step explanation:

The first number is repeating; the second is not. This will cause the first 2 to disappear but the rest will remain.

0.022222.. - 0.02 = 0.0022222..

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3 years ago

What are the first multiples of 12?

dangina [55]

Answer:

1,2,3,4,6,12

Step-by-step explanation:

The first multiples of 12 are 1,2,3,4,6,12

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3 years ago

The longest side of an acute triangle measures 30 inches. The two remaining sides are congruent, but their length is unknown.

lakkis [162]

The smallest perimeter is 72.44 inches. The longest side of an acute triangle measures 30 inches. The two remaining sides are congruent, but their length is unknown. As much as possible, the sum of the length of the two remaining side must be greater than the other side. Given the side is 30, then the sum of the two remaining sides should be greater than 30 inches.

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3 years ago

A drawer is filled with 7 black shirts,5 white shirts,10 gray shirts. one shirt is chosen at random from the drawer. find the pr

nignag [31]

12/22 will be your answer

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4 years ago

An object is dropped from a small plane. As the object falls, its distance, d, above the ground after t seconds, is given by the

DedPeter [7]

The inequality can be used to find the interval of time taken by the object to reach the height greater than 300 feet above the ground is:

$d = -16t^2 + 1000$

Solution:

The object falls, its distance, d, above the ground after t seconds, is given by the formula:

$d = -16t^2 + 1000$

To find the time interval in which the object is at a height greater than 300 ft

Frame a inequality,

$-16t^2 + 1000 > 300$

Solve the inequality

Subtract 1000 from both sides

$-16t^2 + 1000 - 1000 > 300 - 1000\\\\-16t^2 > -700$

$16t^2 < 700\\\\Divide\ both\ sides\ by\ 16\\\\t^2 < \frac{700}{16}\\\\Take\ square\ root\ on\ both\ sides\\\\t < \sqrt{\frac{700}{16}}\\\\t < \pm 6.61$

Time cannot be negative

Therefore,

t < 6.61

And the inequality used is: $-16t^2 + 1000>300$

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3 years ago