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PilotLPTM [1.2K]
3 years ago
13

The Masim family's monthly budget is shown in the circle graph. The family has a monthly income of $5,000. How much money do the

y spend on food each month? Emergency fund 5%, transportation 5%, medical 22%, clothing 6%, entertainment 7%, savings 10%, food 15%, housing 30%
Mathematics
1 answer:
Makovka662 [10]3 years ago
3 0
$5000*15%
Because for food they spend 15% of their monthly income...
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Tell whether I and y are proportional<br><br> PLS HELP
pentagon [3]

Answer:

This is not proportional. In order for it to be proportional the number from dividing y/x must be the same all the way through. Example:18/2=9 20/4=5

The answers are not the same, therefore x and y are not proportional. Hope this helped.

Step-by-step explanation:

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7x – 4 = 5x - x + 35 whats the value of x?​
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Step-by-step explanation:

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An object starts from rest and accelerates at a rate of 3.0 meters per second2 for 6.0 seconds. The velocity of the object at th
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a= v-u/t

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3 years ago
The area of a circle is 16pi cm2. What is the circle's circumstance?
gavmur [86]
I think you mean circumference...Area is A= \pi  r^{2}. We have the area so we need to use it to solve for the radius which we will then use in the circumference formula.  16 \pi = \pi  r^{2}.  Divide both sides by pi to get \frac{16 \pi }{ \pi } = r^{2}.  Of course the simplification of the left side gives us 16= r^{2} and r = 4.  Now fill that in to the circumference formula, which is C=2 \pi r, to get CC=2 \pi (4) which is a circumference of 8 \pi
4 0
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Between 0 degrees Celsius and 30 degrees Celsius, the volume V (in cubic centimeters) of 1 kg of water at a temperature T is giv
Ira Lisetskai [31]

Answer:

T = 3.967 C

Step-by-step explanation:

Density = mass / volume

Use the mass = 1kg and volume as the equation given V, we will come up with the following equation

D = 1 / 999.87−0.06426T+0.0085043T^2−0.0000679T^3

   = (999.87−0.06426T+0.0085043T^2−0.0000679T^3)^-1

Find the first derivative of D with respect to temperature T

dD/dT = \dfrac{70000000\left(291T^2-24298T+91800\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^2}

Let dD/dT = 0 to find the critical value we will get

\dfrac{70000000\left(291T^2-24298T+91800\right)}  = 0

Using formula of quadratic, we get the roots:

T =  79.53 and T = 3.967

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Find 2nd derivative to check whether the equation will have maximum value:

-\dfrac{140000000\left(395178T^4-65993368T^3+3286558821T^2+2886200857800T-121415215620000\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^3}

Substituting the value with T=3.967,

d2D/dT2 = -1.54 x 10^(-8)    a negative value. Hence It is a maximum value

Substitute T =3.967 into equation V, we get V = 0.001 i.e. the volume when the the density is the highest is at 0.001 m3 with density of

D = 1/0.001 = 1000 kg/m3

Therefore T = 3.967 C

3 0
3 years ago
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