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Serggg [28]
3 years ago
11

What is the cheapest way to buy 48 cans of cola

Mathematics
1 answer:
Inga [223]3 years ago
4 0

Answer:

both the first one

Step-by-step explanation:

use unit rate

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Aaron works as a bar attendant and receives $11 per hour. On Saturday he works for five hours at normal time and three hours ove
scoundrel [369]

Answer:

so his total pay for Saturday would be $104.50

Step-by-step explanation:

He works 5 hours at $11  per hour which gets a total of 55$

He also works 3 hours of overtime where he gets payed 1.5x pay

11 x 1.5 = 16.5 (10x1.5 = 15 1x1.5 = 1.5)

so he gets $16.5 per hour for 3 hours which = 49.5$

49.5 + 55 = $104.50

5 0
3 years ago
Write (-5+8i)+(-5-8i) as a complex number in standard form
gizmo_the_mogwai [7]
(-5+8i)+(-5-8i) =
-5+8i-5-8i=-10
5 0
3 years ago
Help help help help math please ASAP
Zigmanuir [339]

Answer:

I think its 86

Step-by-step explanation:

As the two lines going in the same direction are parallel and angles within parallel lines add to 180.

so 180-94=86

7 0
2 years ago
Read 2 more answers
In a basketball game Anya makes 14 baskets. Some of these baskets were worth 2-points and others were worth 3-points. In total s
Tems11 [23]

Answer:

She made 12 two point basket.

Step-by-step explanation:

Assuming the number of 2 point basket is x and that of 3 point basket is y.

Based on the question the total numbers of basket is 14, that is x + y = 14 , and the total numbers of points is 30, which helps us with our second equation 2(x) +3(y)=30.

x + y = 14 eqn 1

2(x) +3(y)=30 eqn 2

Using elimination method multiplying eqn 1 by -3 and adding it to equation 2

-3x-3 y = -42 adding to eqn 2 gives

-x= -12

x=12. Which gives the number of the 2 points basket she made .

7 0
3 years ago
Make a the subject of a2+b2=c2
wel

Answer:

a=\sqrt{c^2-b^2

⇒ a=\sqrt{(c+b)(c-b)}        [Factorized form]

Step-by-step explanation:

Given expression:

a^2+b^2=c^2

We need to make a the subject.

In order to do that we need to solve the expression for a in terms of b and c

We have,

a^2+b^2=c^2

Subtracting both sides by b^2

a^2+b^2-b^2=c^2-b^2

a^2=c^2-b^2

Taking square root both sides in order to remove square of a

\sqrt{a^2}=\sqrt{c^2-b^2}

a=\sqrt{c^2-b^2

The difference of squares can be factorized and written  as:

a=\sqrt{(c+b)(c-b)}    [difference of squares x^2-y^2=(x+y)(x-y) ]

4 0
3 years ago
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