SOMEONE PLEASE HELP ME ASAP PLEASEEEE!!!!

Mathematics

2 answers:

Andru [333]3 years ago

8 0

Answer:

mx4. I am not completely sure but they are doing -x4 on each of them

Step-by-step explanation:

MariettaO [177]3 years ago

4 0

M times 4 is the answer

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Need help to do this step by step please <br> 3x2 - 2x=-1

sdas [7]

Answer:

Solving the expression $3x^2-2x=-1$ we get: $\mathbf{x=\frac{1+\sqrt{2}i }{3}\:or\:x=\frac{1-\sqrt{2}i }{3}}$

Step-by-step explanation:

We need to solve the expression: $3x^2-2x=-1$

This is a quadratic expression and it can be solved using quadratic formula

Solving:

$3x^2-2x=-1\\$

we can write it as:

$3x^2-2x+1=0$

The quadratic formula is: $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

where a = 3, b = -2 and c= 1

Putting values and solving:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{-(-2)\pm\sqrt{(-2)^2-4(3)(1)}}{2(3)}\\x=\frac{2\pm\sqrt{4-12}}{2(3)}\\x=\frac{2\pm\sqrt{-8}}{6}\\We\:know\:that\:\sqrt{-1}=i\\x=\frac{2\pm\sqrt{8}\sqrt{-1} }{6} \\We\:know\:\sqrt{8}=\sqrt{2\times 2 \times 2}=\sqrt{2^2 \times 2}=2\sqrt{2} \\x=\frac{2\pm2\sqrt{2}i }{6}\\Now,\\x=\frac{2+2\sqrt{2}i }{6}\:or\:x=\frac{2-2\sqrt{2}i }{6}\\x=\frac{2(1+\sqrt{2}i) }{6}\:or\:x=\frac{2(1-\sqrt{2}i) }{6}\\x=\frac{1+\sqrt{2}i }{3}\:or\:x=\frac{1-\sqrt{2}i }{3}$

So, solving the expression $3x^2-2x=-1$ we get: $\mathbf{x=\frac{1+\sqrt{2}i }{3}\:or\:x=\frac{1-\sqrt{2}i }{3}}$

8 0

3 years ago

Based only on the information given in the diagram it is guaranteed that RST UVW

lapo4ka [179]

Answer:

The triangles are similar

Step-by-step explanation:

We are given and two angles so by default we know the third angle. We know the three angles are the same, so the triangles are similar by AAA. We do not about conqruency without a side length.

6 0

3 years ago

Read 3 more answers

HELP PLEASE 30 POINTS! WILL MARK BRAINLIEST IF CORRECT!!!!!

KATRIN_1 [288]

Answer:

See Below.

Step-by-step explanation:

We want to verify:

$\cos(x-y)-\cos(x+y)=2\sin(x)\sin(y)$