Which of the following is considered a model for enzyme action

Sarita used 54 ounces of apples to make an apple pie.How many pounds and ounces of apple did sarita use?

Inga [223]

Answer:

C

Step-by-step explanation:

16 ounces is equal to 1 pound

Divide 54 by 16 and you get 3.375

You know that there are 3 pounds now, so subtract 3 from what you got to get 0.375

Now multiply 0.375 by 16 to turn it back into ounces, which is 6

3 pounds and 6 ounces is answer choice C

8 0

3 years ago

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A survey of 1,562 randomly selected adults showed that 522 of them have heard of a new electronic reader. The accompanying techn

tester [92]

Answer:

a) We want to test the claim that 35% of adults have heard of the new electronic reader, then the system of hypothesis are.:

Null hypothesis: $p=0.35$

Alternative hypothesis: $p \neq 0.35$

And is a two tailed test

b) $z=\frac{0.334 -0.35}{\sqrt{\frac{0.35(1-0.35)}{1562}}}=-1.326$

c) $p_v =2*P(z$

d) Null hypothesis: $p=0.35$

e) Fail to reject the null hypothesis because the P-value is greater than the significance level, alpha.

Step-by-step explanation:

Information provided

n=1562 represent the random sample selected

X=522 represent the people who have heard of a new electronic reader

$\hat p=\frac{522}{1562}=0.334$ estimated proportion of people who have heard of a new electronic reader

$p_o=0.35$ is the value to verify

$\alpha=0.05$ represent the significance level

z would represent the statistic

$p_v$ represent the p value

Part a

We want to test the claim that 35% of adults have heard of the new electronic reader, then the system of hypothesis are.:

Null hypothesis: $p=0.35$

Alternative hypothesis: $p \neq 0.35$

And is a two tailed test

Part b

The statistic for this case is given :

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the info given we got:

$z=\frac{0.334 -0.35}{\sqrt{\frac{0.35(1-0.35)}{1562}}}=-1.326$

Part c

We can calculate the p value using the laternative hypothesis with the following probability:

$p_v =2*P(z$

Part d

The null hypothesis for this case would be:

Null hypothesis: $p=0.35$

Part e

The best conclusion for this case would be:

Fail to reject the null hypothesis because the P-value is greater than the significance level, alpha.

5 0

3 years ago

Help me give alot of pointz

VashaNatasha [74]

Answer:

1. 2560000

2. 256000

3. 256000

4. 2560000

7 0

1 year ago

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When the p-value is used for hypothesis testing, the null hypothesis is rejected if _____

pashok25 [27]

Answer:

B

Step-by-step explanation:

Here, we are to give the reason why we would reject the null hypothesis during the hypothesis testing.

In considering whether to accept the null hypothesis or reject the null hypothesis, we have to take into consideration two things.

The p-value and the alpha value. The p-value refers to the probability which is directly obtainable from the standard score which is referred to as the z-score while the alpha refers to the level of significance.

Now, when the p-value is less than alpha, we simply reject the null hypothesis and accept the alternative hypothesis. In a case however, we have the value of p greater than or equal to the significance level alpha, we simply accept the null hypothesis in this case.

The question asks for a rejection case and this can happen only when the p-value is less than the level of significance alpha

5 0

3 years ago

Is it true or false lollll

Reika [66]

Answer:

I think true im sorry if its not

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3 years ago

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