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1 year ago

6

Miss lead says that if y varies directly with x and y=15 when x=-3, then y=-20 when x=4. Is she correct? Answer in complete sent

ences and show work. (PLEASE ANSWER ASAP)

1 answer:

gizmo_the_mogwai [7]1 year ago

6 0

Answer:

Yes, she is correct.

Step-by-step explanation:

y = kx is direct variation

15 = k*-3

k = -5.

So the equation of variation is

y = -5x

When x = -4:

y -5*-4 = 20.

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Anettt [7]

Answer: 554

Step-by-step explanation:

If prior population proportion is known, then the formula to find the sample size is given by :-

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As per given description, we have

p= 0.1

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Then,

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3 years ago

Help me please if your right ill give you the brainliest (mybad if i spelled it wrong)

Elina [12.6K]

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2 years ago

Given that <img src="https://tex.z-dn.net/?f=I_0%20%3D%2010%5E-12" id="TexFormula1" title="I_0 = 10^-12" alt="I_0 = 10^-12" alig

Alex Ar [27]

The intensity of sound which the decibel level of the sound measures 156 is 3.981 × 10³ W/m²

Decibel level, dB = 10log₁₀(I/I₀) where dB = decibel level = 156, I = intensity at 156 dB and I₀ = 10⁻¹² W/m².

Since we require I, making I subject of the formula, we have

dB/10 = log₁₀(I/I₀)

$\frac{I}{I_{0} } = 10^{\frac{dB}{10} } \\I = I_{0} 10^{\frac{dB}{10} }$

Substituting the values of the variables into the equation, we have

$I = I_{0} 10^{\frac{dB}{10} }\\I = 10^{-12} 10^{\frac{156}{10} }\\I = 10^{-12} 10^{15.6}\\I = 10^{15.6-12} \\I = 10^{3.6} W/m^{2}$

I = 3981.072W/m²

I = 3.981 × 10³ W/m²

So, the intensity of sound which the decibel level of the sound measures 156 is 3.981 × 10³ W/m²

Learn more about intensity of sound here:

brainly.com/question/4431819

3 0

2 years ago

IrinaVladis [17]

Answer:

y-5=(x-6)?

Step-by-step explanation:

Hope this helped!

-BB

3 0

2 years ago

What is the distance between (-1,4) and (2,0)

Ivahew [28]

Answer: 5

The Distance between the coordinates of two points is measured by distance formula.

Step-by-step explanation:

The Distance between the coordinates of two points P(x1,y1) and Q(x2,y2) is measured by

Distance PQ= $\sqrt{}$ (x2-x1)²+(y2-y1)²

So, the distance between (-1,4 ) and (2,0) can be calculated by

Distance= $\sqrt{}$ (2-(-1))²+(0-4)²

= $\sqrt{}$ (3)²+(-4)²

= $\sqrt{}$ 9+16 = $\sqrt{}$ 25 as $\sqrt{}$ 25 = 5

Distance = 5

So the distance between the two coordinates is 5.

7 0

2 years ago