Answer:
11 cats
Step-by-step explanation:
Given :
Jane's initial = 23
My initial = 2
Jane gives out 5 cats to me ;
Jane's new = 23 - 5 = 18
My new = 2 + 5 = 7
Number of cats Jane has than me :
Jane's new - My new
18 - 7 = 11 cats
Second question is incomplete. We aren't told what to calculate.
Answer:
5.25 times (5 if rounded)
Step-by-step explanation:
7/8=21/24
1/6=4/24
21/4=5.25
9514 1404 393
Answer:
a: 0; b: 1; c: 1; d: ∞; e: 0; f: ∞
Step-by-step explanation:
Simplify the expressions to put the left and right in the same form. Then compare. If the x-coefficients are the same, there will be 0 or ∞ solutions. If they are different, there will be 1 solution.
If the x-coefficients are the same, look at the constants. If they are different, there will be 0 solutions. If they are the same, there will be ∞ solutions.
__
a) -2x -10 = -6x +4x -8 ⇒ -2x -10 = -2x -8 . . . . 0 solutions
b) 0.8x -4.8 = -0.5x +3.4 . . . . 1 solution
c) -1/4x -7/2 = -3x -4 . . . . 1 solution
d) 2x -8 +x = 3x -6 -2 ⇒ 3x -8 = 3x -8 . . . . ∞ solutions
e) 3 -2/5x -12/5 = 2 -2/5x ⇒ -2/5x +3/5 = -2/5x +2 . . . . 0 solutions
f) 6x -6 +21 = 6x +15 ⇒ 6x +15 = 6x +15 . . . . ∞ solutions
Answer:
10 to the third power is 10x10x10 which is 1000. So you do 0.15 x 1000 which equals 150. So the answer is 150
Step-by-step explanation:
Answer:
Step-by-step explanation:
In this particular case we have the following system of equations:
y
=
−
3
x
+
4
[
E
q
.
1
]
x
+
4
y
=
−
6
[
E
q
.
2
]
Substituting
[
E
q
.
1
]
in
[
E
q
.
2
]
:
x
+
4
(
−
3
x
+
4
)
=
−
6
Applying the distributive property on the left side:
x
−
12
x
+
16
=
−
6
Simplifying
:
−
11
x
=
−
22
Solving for
y
:
x
=
−
22
−
11
=
2
Substituting
x
=
2
in
[
E
q
.
1
]
:
y
=
−
3
(
2
)
+
4
=
−
2
Therefore
, the solutions are
x
=
2
and
y
=
−
2