(6-3)÷3-6+2 show work
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When you multiply two complex numbers given in polar form, the argument of the product is the sum of the arguments of the factors. Meanwhile, the modulus of the product is the product of the moduli of the factors.
In this case, you'd have
and the modulus would simply be
. Since
we would expect the final product to fall in the first quadrant.
In this case, you'd have
and the modulus would simply be
we would expect the final product to fall in the first quadrant.