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3 years ago

A right triangle has a height of 10 feet and an base of 4x^2y+2xy^2 feet. Find the area.show work to justify your answer (a=1/2)

1 answer:

5 0

Givens
h = 10
b = 4x^y + 2xy^2

Formula
Area = 1/2 b * h

Solution
Substitute the givens into the formula
Area = 1/2 * 10 * (4x^2y + 2xy^2)
Area = 5 * (4x^2y + 2xy^2) What to do next? I would remove the brackets
Area = 5 * 4x^2y + 5 * 2xy^2
Area = 20x^2y + 10xy^2 <<<< Answer

Also possible is to take out more common factors.
The common factor of 4x^2y + 2xy^2 is 2xy and what is left over is 2x + y

So you would have Area = 5*2xy(2x + y)

If you have been given answers please list them.

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Help pls if u can pls

Vadim26 [7]

Answer:

Infinite solutions.

Step-by-step explanation:

Let's solve your system by substitution.

3y=9x+15;3x−y=−5

Rewrite equations:

3x−y=−5;3y=9x+15

Step: Solve 3x−y=−5 for y:

3x−y=−5

3x−y+−3x=−5+−3x(Add -3x to both sides)

−y=−3x−5

−y −1 −1=−3x−5

(Divide both sides by -1)

y=3x+5

Step: Substitute 3x+5 for y in 3y=9x+15:

3y=9x+15

3(3x+5)=9x+15

9x+15=9x+15(Simplify both sides of the equation)

9x+15+−9x=9x+15+−9x(Add -9x to both sides)

15=15

15+−15=15+−15(Add -15 to both sides)

0=0

Hello lucker

8 0

2 years ago

Please Help!!!! Solve For L

Sonja [21]

<h3>Given :</h3>

$\tt B = L - L a f$

L = ?

<h3>Solution :</h3>

$\tt B = L - L a f$

By taking L common from $\tt (L - L a f)$ , we get :

$\tt : \implies B = L(1 - a f)$

$\tt : \implies \dfrac{B}{(1 - a f)} = L$

$\tt : \implies L = \dfrac{B}{1 - a f}$

Hence, value of $\tt L = \dfrac{B}{1 - a f}$

4 0

3 years ago

Read 2 more answers

A study was recently conducted to estimate the mean cholesterol for adult males over the age of 55 years. From a random sample o

Komok [63]

Answer: Correct critical value = 2.2622

Step-by-step explanation:

Confidence interval for population mean when population standard deviation is unknown:

$\overline{x}\pm t_{\alpha/2}\dfrac{s}{\sqrt{n}}$ , where $\overline{x}$ = sample mean, n= sample size, s= sample standard deviation, $t_{\alpha/2}$ = two-tailed t value.

As per given: n= 10

degree of freedom : df = n-1=9

$\overline{x}=242.6\\\\s=73.33\\\\\alpha=5\%=0.05$

Critical t-value : $t_{\alpha/2,df}=t_{0.05/2,9}=t_{0.025,9}=2.2622$

So, the 95 percent confidence interval estimate for the mean :

$242.6\pm (2.2622)\dfrac{73.33}{\sqrt{10}}\\\\=242.6\pm (2.2622)(23.19)\\\\\approx242.6\pm52.46\\\\=(242.6-52.46,\ 242.6+52.46)\\\\=(190.14,\ 295.06)$