First find the rate of growth using the formula of A=p e^rt A 7200 P 6000 E constant R rate of growth? T time 6 hours We need to solve for r R=[log (A/p)÷log (e)]÷t R=(log(7,200÷6,000)÷log(e))÷6 R=0.03 rate of growth
Now predict how many bacteria will be present after 17 hours using the same formula A=p e^rt A ? P 6000 R 0.03 E constant T 17 hours A=6,000×e^(0.03×17) A=9,991.7 round your answer to get A=9992