Question

A black rooster mates with a white hen. Based on their genotypes, the chance that the offspring will be checkered is 100 percent. What is the rooster genotype? What is the hen’s genotype?

Answer 1

The rooster and the hen must be homozygous dominant for their phenotypes, in order for their chicks to display both phenotypes. 

Rooster= BB (Homozygous dominant for black color) 
Hen= WW (Homozygous dominant for white color) 

Answer 2

Answer:

Rooster's genotype is  BB

hen's genotype is bb

Explanation:

Let the allele for black color be "B"

and the allele for white color be "b"

let us assume that B is dominant over b

Thus,

Genotype of black rooster mate can be either BB or Bb

Genotype of white hen would be "bb" as b is a recessive allele.

Now it is given that all the offspring produced are checkered

This can happen only when BB is crossed with Bb, so that all the offspring are checkered with genotype "Bb"

So ,

Rooster's genotype is  BB

hen's genotype is bb