3 years ago

Please help me on this question

1 answer:

4 0

It is the right answer........

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Step-by-step explanation:

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cluponka [151]

Answer: (D) 16%

Step-by-step explanation:

Binomial probability formula :-

$P(x)=^nC_xp^x(1-p)^n-x$ , where n is the sample size , p is population proportion and P(x) is the probability of getting success in x trial.

Given : The proportion of students in College are near-sighted : p= 0.28

Sample size : n= 20

Then, the the probability that in a randomly chosen group of 20 College students, exactly 4 are near-sighted is given by :_

$P(x=4)=^{20}C_4(0.28)^4(1-0.28)^{20-4}\\\\=\dfrac{20!}{4!16!}(0.28)^4(0.72)^{16}\\\\=0.155326604912\approx0.16\%$

Hence, the probability that in a randomly chosen group of 20 College students, exactly 4 are near-sighted is closest to 16%.

7 0

3 years ago