Answer:
the answer is (-1,2), hope this helps.
Answer:
The probability is ![P(|p-\^{p}| > 0.03) = 0.0040](https://tex.z-dn.net/?f=P%28%7Cp-%5C%5E%7Bp%7D%7C%20%3E%20%200.03%29%20%20%3D%20%20%200.0040)
Step-by-step explanation:
From the question we are told that
The population proportion is ![p = 0.07](https://tex.z-dn.net/?f=p%20%3D%20%200.07)
The mean of the sampling distribution is ![\mu_p = 0.07](https://tex.z-dn.net/?f=%5Cmu_p%20%3D%20%200.07)
The sample size is n = 600
Generally the standard deviation is mathematically represented as
![\sigma_p = \sqrt{\frac{p (1 -p)}{n} }](https://tex.z-dn.net/?f=%5Csigma_p%20%20%3D%20%20%5Csqrt%7B%5Cfrac%7Bp%20%281%20-p%29%7D%7Bn%7D%20%7D)
=>
=>
Generally the probability that the proportion of airborne viruses in a sample of 600 viruses would differ from the population proportion by greater than 3% is mathematically represented as
![P(|p-\^{p}| > 0.03) = 1 - P(|p -\^{p}| \le 0.03)](https://tex.z-dn.net/?f=P%28%7Cp-%5C%5E%7Bp%7D%7C%20%3E%20%200.03%29%20%3D%20%201%20-%20P%28%7Cp%20-%5C%5E%7Bp%7D%7C%20%5Cle%200.03%29)
=> ![P(|p-\^{p}| > 0.03) = 1 - P(-0.03 \le p -\^{p} \le 0.03 )](https://tex.z-dn.net/?f=P%28%7Cp-%5C%5E%7Bp%7D%7C%20%3E%20%200.03%29%20%20%3D%20%201%20-%20%20P%28-0.03%20%5Cle%20p%20-%5C%5E%7Bp%7D%20%5Cle%200.03%20%29)
Now add p to both side of the inequality
=> ![P(|p-\^{p}| > 0.03) = 1 - P( 0.07-0.03 \le \^{p} \le 0.03+ 0.07 )](https://tex.z-dn.net/?f=P%28%7Cp-%5C%5E%7Bp%7D%7C%20%3E%20%200.03%29%20%20%3D%20%201%20-%20%20P%28%200.07-0.03%20%20%5Cle%20%5C%5E%7Bp%7D%20%5Cle%200.03%2B%200.07%20%29)
=> ![P(|p-\^{p}| > 0.03) = 1 - P(0.04 \le \^{p} \le 0.10 )](https://tex.z-dn.net/?f=P%28%7Cp-%5C%5E%7Bp%7D%7C%20%3E%20%200.03%29%20%20%3D%20%201%20-%20%20P%280.04%20%5Cle%20%5C%5E%7Bp%7D%20%5Cle%200.10%20%29)
Now converting the probabilities to their respective standardized score
=>
=> ![P(|p-\^{p}| > 0.03) = 1 - P(-2.88 \le Z \le 2.88 )](https://tex.z-dn.net/?f=P%28%7Cp-%5C%5E%7Bp%7D%7C%20%3E%20%200.03%29%20%20%3D%20%201%20-%20%20P%28-2.88%20%20%5Cle%20Z%20%5Cle%202.88%20%29)
=> ![P(|p-\^{p}| > 0.03) = 1 - [P(Z \le 2.88) - P(Z \le -2.88)]](https://tex.z-dn.net/?f=P%28%7Cp-%5C%5E%7Bp%7D%7C%20%3E%20%200.03%29%20%20%3D%20%20%201%20-%20%5BP%28Z%20%5Cle%202.88%29%20-%20P%28Z%20%5Cle%20-2.88%29%5D)
From the z-table
![P(Z \le 2.88) = 0.9980](https://tex.z-dn.net/?f=P%28Z%20%5Cle%202.88%29%20%20%3D%20%200.9980)
and
![P(Z \le -2.88) = 0.0020](https://tex.z-dn.net/?f=P%28Z%20%5Cle%20-2.88%29%20%20%3D%200.0020)
So
![P(|p-\^{p}| > 0.03) = 1 - [0.9980 - 0.0020]](https://tex.z-dn.net/?f=P%28%7Cp-%5C%5E%7Bp%7D%7C%20%3E%20%200.03%29%20%20%3D%20%20%201%20-%20%5B0.9980%20-%200.0020%5D)
=> ![P(|p-\^{p}| > 0.03) = 0.0040](https://tex.z-dn.net/?f=P%28%7Cp-%5C%5E%7Bp%7D%7C%20%3E%20%200.03%29%20%20%3D%20%20%200.0040)
Answer:
8:2
32:8
Step-by-step explanation:
It's pretty simple:
If there's 32 boys, which is 4 times the amount you start with, you have to apply that to the number of girls as well since for every 8 boys, there is 2 girls.
8x4
2x4
32:8 Hope this helps
»»————- ★ ————-««
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<em>Hey, love!</em>
<em>This questions seems to require some type of visual or video. It might help if you go check out what your teacher gave you with this and then come back!</em>
★ ★ ★
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