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Tom [10]
3 years ago
15

Please answer asap (don't need explanation)

Mathematics
1 answer:
Zanzabum3 years ago
6 0

Answer:

The slope is 60.

Points for the graph are: (0,0), (1, 60), (2, 180), (3, 240), (4, 320), (5, 400), (6, 480), (7, 560)

Step-by-step explanation:

I don't know what the question is but I will tell you your graph is horribly wrong.

The points for the graph is:

(0,0), (1, 60), (2, 180), (3, 240), (4, 320), (5, 400), (6, 480), (7, 560)

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4 0
1 year ago
Help needed for MATH problem
vivado [14]

Answer:

1/ 10 ; 1/15

Step-by-step explanation:

Given that:

Fraction with brown hair = 2 /5

1/4 of brown haired girls have long hairs

2/3 of long, brown haired girls have green eyes.

Fraction of girls with long, brown hair :

1/4 of 2/5

1/4 * 2/5 = (1*2) / (4*5) = 2/ 20 = 1/10

Fraction with long, brown hair and green eyes :

2/3 of Fraction with long, brown hair :

2/3 of 1/10

2/3 * 1/10 = (2*1) / (3*10) = 2/30 = 1/15

5 0
3 years ago
Can someone please give me the answer to this
Rasek [7]

Answer:

The answer is (4, -6)

Step-by-step explanation:

Point C starts at (2, -5). The triangle moves 2 units right, so 2 + 2 = 4 and 1 unit down, so -5 - 1 = -6

4 0
3 years ago
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pishuonlain [190]

Answer:

b hope it helps

Step-by-step explanation:

8 0
3 years ago
The local public transport authority is conducting research into commuter behaviour. A previous census indicated that the mean c
kondor19780726 [428]

Answer:

H_0:\mu  = 45 and H_a:\mu  < 45

T = 34.88

The null hypothesis is not rejected

Step-by-step explanation:

Given

Random sample of 50 commuter times

Solving (a): The null and alternate hypothesis

From the question, a previous census shows that:

\mu =45 and \sigma= 9.1

This is the null hypothesis i.e.

H_0:\mu  = 45

Reading further, a new test was to show whether the average has decreased.

This is the alternate hypothesis, and it is represented as:

H_a:\mu  < 45

Solving (b) and (c): The test statistic (T).

This is calculated using:

T = \frac{\mu}{\sigma/\sqrt n}

In this case:

n = 50   \mu =45 and \sigma= 9.1

So:

T = \frac{45}{9.1/\sqrt{50}}

T = \frac{45}{9.1/7.07}

T = \frac{45}{1.29}

T = 34.88

Solving (c): Accept or reject null hypothesis

\alpha = 0.05

First calculate the degrees of freedom (df)

df = n - 1 = 50 - 1

d f = 49

From the t distribution table,

At: d f = 49,  \alpha = 0.05 and T = 34.88

the t score is:

p = 1.676

p > 0.05

<em>So, the null hypothesis is not rejected</em>

7 0
3 years ago
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