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PIT_PIT [208]
3 years ago
10

Blake and Ned work for a home remodeling business. They are putting the final touches on a home they renovated. Working alone, B

lake can paint one room in 9 hours. Ned can paint the same room in 6 hours. How long will it take them to paint the room if they work together?
Mathematics
2 answers:
gizmo_the_mogwai [7]3 years ago
7 0

Answer: The time taken by both of them if they work together is given by

3\dfrac{3}{5}\ hours

Step-by-step explanation:

Since we have given that

Time taken by Blake to paint one room = 9 hours

Time taken by Ned to paint one room = 6 hours

Work done by Blake  = \dfrac{1}{9}

Work done by Ned = \dfrac{1}{6}

Total work done by both of them together is given by

\dfrac{1}{6}+\dfrac{1}{6}\\\\=\dfrac{3+2}{18}\\\\=\dfrac{5}{18}

So, the time taken by both of them if they work together is given by

\dfrac{18}{5}=3\dfrac{3}{5}\ hours

jek_recluse [69]3 years ago
4 0

Blake can do the work in 9 and part of work in 1 hour = 1/9

Ned can paint the same room in six hours, as well as do part of work in 1 hour = 1/6

If they do it together = 1/9+1/6=5/118, and they can do 5/18 part of work in hour = 1

So, they can do whole work in hours = 1/5/18=3.6

So if they do it together it will only take 3.6 hours.

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fiasKO [112]

Answer:

384 cm

Step-by-step explanation:

Perimeter is the sum of all external sides. (do not mix this up with area. Perimeter is the easy one) :)

There are 4 external sides.

Top = bottom = 132 cm

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Add all 4 sides:

2(132) + 2(60)

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1 year ago
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Arturiano [62]

Answer:

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Step-by-step explanation:

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2 years ago
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Pls, help me with this math question
olya-2409 [2.1K]

Answer:

Perimeter \sqrt{26}+\sqrt{5}+\sqrt{10}+\sqrt{17} units.  Area 12 square units.

Step-by-step explanation:

Perimeter: total distance around the figure.

Distance Formula:  the distance between points \left(x_1,y_1\right) \text{ and } \left(x_2,y_2\right) is

d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

AB=\sqrt{(6-1)^2+(2-1)^2}=\sqrt{25+1}=\sqrt{26}

BC=\sqrt{(5-6)^2+(4-2)^2}=\sqrt{1+4}=\sqrt{5}CD=\sqrt{(2-5)^2+(5-4)^2}=\sqrt{9+1}=\sqrt{10}DA=\sqrt{(1-2)^2+(1-5)^2}=\sqrt{1+16}=\sqrt{17}

The perimeter is the sum of all those segment lengths.

One way to find the area of the figure is to surround it with a rectangle, insert some lines so that the areas you do not want can be found and subtracted from the rectangle's area.  (See attached image.)

The area of the large rectangle around the figure is 5 x 4 = 20 square units.

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2 + 1.5 + 1 + 2.5 + 1 = 8 square units

Subtract 8 from the surrounding rectangle's area of 20, and you get the area of the figure is 20 - 8 = 12 square units.

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3 years ago
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