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3 years ago

Which steps can be done to both sides of the equation to determine the value of x ?

Mathematics

1 answer:

exis [7]3 years ago

6 0

Answer:

<h3>- Add 9.6 to both sides of the equation </h3><h3>- Divide both side by the coefficient of x i.e 3.2</h3><h3></h3>

Step-by-step explanation:

The first step that can be done to both of the equation given is to add 9.6 to both sides of the equation as shown;

3.2x – 9.6 = 38.4

3.2x – 9.6+9.6 = 38.4+9.6

3.2x = 38.4+9.6

3.2x = 48.0

step 2;

Divide both side by the coefficient of x i.e 3.2

3.2x/3.2 = 48.0/3.2

x = 15

Therefore the value of x is 15

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7. Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

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Hey there!

Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

Answer :

x = -4 or x = 2 ✅

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Quadratic formula : ax² + bx + c = 0 where a ≠ 0

The number of real-number solutions (roots) is determined by the discriminant (b² - 4ac) :

If b² - 4ac > 0 , There are 2 real-number solutions

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If b² - 4ac < 0 , There is no real-number solution.

The roots of the equation are determined by the following calculation:

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b² - 4ac = 36 > 0 ; The equation admits two real-number solutions

2) Calculate the roots of the equation:

▪️ (1)

$x_1 = \frac{ - b - \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ x_1 = \frac{ - 2 - \sqrt{36} }{2(1) } \\ \\ x_1 = \frac{ - 2 - 6}{2} \\ \\ x_1 = \frac{ - 8}{2} \\ \\ \blue{\boxed{\red{x_1 = -4}}}$

▪️ (2)

$x_2 = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ x_2 = \frac{ - 2 + \sqrt{36} }{2(1)} \\ \\ x_2 = \frac{ - 2 + 6}{2} \\ \\ x_2 = \frac{4}{2} \\ \\ \red{\boxed{\blue{x_2 = 2}}}$

>> Therefore, your answers are x = -4 or x = 2.

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