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3 years ago

Rhonda bought 1.6 pounds of peaches for $.60 and 3.5 pound of apples for $1.75. Which

Mathematics

2 answers:

nekit [7.7K]3 years ago

7 0

Answer:

Apples

Step-by-step explanation:

(Peaches) First is divide 1.6 lbs. by 1.6 to get 1 pound and 0.6 by 1.6 to get $0.375 ($0.38) so 1 pound of peaches are $0.38

(Apples) Second is divide 3.5 by 3.5 to get 1 pound and $1.75 by 3.5 to get $0.50 so 1 pound of apples are $0.50

(Third) $0.38 < $0.50

castortr0y [4]3 years ago

5 0

Answer: Apples

Step-by-step explanation: For this problem we will need to find how much 1 pound of peaches and 1 pound of apples cost to determine which fruit costs more per pound.

Step 1: Divide 1.6 pounds by 1.6 to get 1 pound of peaches. 1.6 divided by 1.6 is 1. Also, divide .60 by 1.6 to determine how much it costs per pound. .60 dived by 1.6 is 0.375.

So, 1 pound of peaches cost about $0.38.

Step 2: Divide 3.5 pounds by 3.5 to get 1 pound of apples. 3.5 divided by 3.5 is 1. Also, divide 1.75 by 3.5 to determine how much it costs per pound. 1.75 divided by 3.5 is 0.5

So, 1 pound of apples cost $0.50

So the apples cost more per pound.

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Graph the function f(x) = (x + 1)(x - 5). Use the drop-

hodyreva [135]

Answer:

3) (2,-9)

4) (0,-5)

5) (1,-8)

Step-by-step explanation:

The vertex will occur between you x-intercepts.

You already found that happens at x=2.

To find the corresponding y-coordinate, replace x in

f(x)=(x+1)(x-5) with 2:

f(2)=(2+1)(2-5)

f(2)=(3)(-3)

f(2)=-9

So the vertex is (2,-9).

The y-intercept is when x=0.

So in f(x)=(x+1)(x-5) replace x with 0:

f(0)=(0+1)(0-5)

f(0)=(1)(-5)

f(0)=-5

So the y-intercept is (0,-5).

To find another point just plug in anything besides any x already used.

We preferably want to use a value of x that will keep us on their grid however far up,down,left, or right their grid goes out. So I'm going to choose something close to the vertex which is at x=2. Let's go with x=1.

So replace x in f(x)=(x+1)(x-5) with x=1:

f(1)=(1+1)(1-5)

f(1)=(2)(-4)

f(1)=-8

So another point to graph is (1,-8).

7 0

3 years ago

Please answer this correctly without making mistakes

satela [25.4K]

Answer:

8940 table spoons and 2 teaspoons

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Samantha sends her son, Barry, to a preschool center on certain days. The cost of preschool is $45 per day along with a fixed mo

MAXImum [283]

Answer:

Step-by-step explanation:

We are given fixed monthly charge = $70.

The cost of preschool per day = $45.

Number of days = d.

Total cost of d days = cost per day × number of days + fixed monthly charge.

Therefore, we get equation

880 = 45×d+70

Now, we need to solve the equation for d.

Subtracting 70 from both sides, we get

880-70 = 45d +70-70

810=45d

Dividing both sides by 45, we get

$\frac{810}{45} =\frac{45d}{45}$

18=d.

Therefore,<em> 18 days Barry attended preschool last month.</em>

<em>Therefore, correct option is D option.</em>

4 0

2 years ago

35 POINTS AVAILABLE

aliina [53]

Answer:

Part 1) The length of each side of square AQUA is $3.54\ cm$

Part 2) The area of the shaded region is $(486\pi-648)\ units^{2}$

Step-by-step explanation:

Part 1)

Find the radius of the circle S

The area of the circle is equal to

$A=\pi r^{2}$

we have

$A=25\pi\ cm^{2}$

substitute in the formula and solve for r

$25\pi=\pi r^{2}$

simplify

$25=r^{2}$

$r=5\ cm$

<em>step 2</em>

Find the length of each side of square SQUA

In the square SQUA

we have that

SQ=QU=UA=AS

$SU=r=5\ cm$

Let

x------> the length side of the square

Applying the Pythagoras Theorem

$5^{2}=x^{2} +x^{2}$

$5^{2}=2x^{2}$

$x^{2}=\frac{25}{2}\\ \\x=\sqrt{\frac{25}{2}}\ cm\\ \\ x=3.54\ cm$

Part 2) we know that

The area of the shaded region is equal to the area of the larger circle minus the area of the square plus the area of the smaller circle

<em>Find the area of the larger circle</em>

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=AB=18\ units$

substitute in the formula

$A=\pi (18)^{2}=324\pi\ units^{2}$

step 2

Find the length of each side of square BCDE

we have that

$AB=18\ units$

The diagonal DB is equal to

$DB=(2)18=36\ units$

Let

x------> the length side of the square BCDE

Applying the Pythagoras Theorem

$36^{2}=x^{2} +x^{2}$

$1,296=2x^{2}$

$648=x^{2}$

$x=\sqrt{648}\ units$

step 3

Find the area of the square BCDE

The area of the square is

$A=(\sqrt{648})^{2}=648\ units^{2}$

step 4

Find the area of the smaller circle

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=(\sqrt{648})/2\ units$

substitute in the formula

$A=\pi ((\sqrt{648})/2)^{2}=162\pi\ units^{2}$

step 5

Find the area of the shaded region

$324\pi\ units^{2}-648\ units^{2}+162\pi\ units^{2}=(486\pi-648)\ units^{2}$

7 0

3 years ago

Katy has 1 3/8 cups of flour. Her cookie recipe calls for 2 cups of flour. How many more cups of flour does she need for the rec

AleksAgata [21]

Subtract the amount you have from the amount you need:

2 cups - 1 3/8 cups

Subtract the whole cup first:

2 cups -1 cup = 1 cup

8/8 = 1

Rewrite 1 as 8/8 then subtract the 3/8 you have:

8/8 - 3/8 = 5/8

You need 5/8 cup more

7 0

2 years ago

Read 2 more answers