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3 years ago

Tell whatever the ordered pair is a solution of the given system.

Mathematics

1 answer:

bagirrra123 [75]3 years ago

5 0

1. No 2. Yes 3. No
I’m pretty sure

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The Inverse Function is one-to-one, find a formula for the inverse. (If anyone could explain how to find this mystical formula,

S_A_V [24]

Step 1. Substitute y for f(x) Step 2. Switch x and y. Step 3. Solve for y. Step 4. Substitute f(x) for y.

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3 years ago

How to solve this problem

guapka [62]

2193 x 10(little 37) over 79

or

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2 years ago

V=1/2at^2 solve for t

malfutka [58]

$\dfrac{1}{2}at^2=V\qquad\text{multiply both sides by 2}\\\\at^2=2V\qquad\text{divide both sides by}\ a\neq0\\\\t^2=\dfrac{2V}{a}\to\boxed{t=\sqrt{\dfrac{2V}{a}}}$

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3 years ago

The surface area of 3ft, 7ft, 2ft

Xelga [282]

Answer: 82 ft squared

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3 years ago

Lim<br> x->infinity (1+1/n)

FrozenT [24]

Answer:

$^{ \lim}_{n \to \infty} (1+\frac{1}{n})=1$

Step-by-step explanation:

We want to evaluate the following limit.

$^{ \lim}_{n \to \infty} (1+\frac{1}{n})$

We need to recall that, limit of a sum is the sum of the limit.

So we need to find each individual limit and add them up.

$^{ \lim}_{n \to \infty} (1+\frac{1}{n})=^{ \lim}_{n \to \infty} (1) +^{ \lim}_{n \to \infty} \frac{1}{n}$

Recall that, as $n\rightarrow \infty,\frac{1}{n} \rightarrow 0$ and the limit of a constant, gives the same constant value.

This implies that,

$^{ \lim}_{n \to \infty} (1+\frac{1}{n})= 1 +0$

This gives us,

$^{ \lim}_{n \to \infty} (1+\frac{1}{n})= 1$

The correct answer is D

5 0

3 years ago