Answer:
db / dt = kb
this becomes b(t) = Ce^(kt)
C = 100, the initial population
P(1) = 420 = 100 e^(1k)
4.2 = e^k
ln 4.2 = k
a) thus, b(t) = 100 e^(t ln 4.2)
b) b(3) = 100 e^(3 ln 4.2)
c) growth constant will still be ln 4.2 (constant percentage of populatioin)
d) 10000 = 100 e^(t ln 4.2)
100 = e^(t ln 4.2)
ln 100 = t ln 4.2
t = ln 100 / ln 4.2
Step-by-step explanation:
Answer:
The one in the middle and the one on the right?
Step-by-step explanation:
I think the answer would be 7.5 hours or 4 hours,not so sure which one exactly
Answer:
Test statistic,
(to 3 dp)
Step-by-step explanation:
Deviation, d = x -y
Sample mean for the deviation


Standard deviation: 


SD =2.93
Under the null hypothesis, the formula for the test statistics will be given by:

