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3 years ago

NEED HELP ASAP!!!!!!!!!!!!!!!

Chemistry

2 answers:

Lisa [10]3 years ago

7 0

Answer:

abyssal

Explanation:

creativ13 [48]3 years ago

6 0

Answer:

The abyssal plains

Explanation:

this is because it is so dark and devoid of resources that it is hard for most forms of life to survive

pls make me brainliest :) I'm trying to become an Ace

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Benzaldehyde and benzyl alcohol can be distinguished by NMR. The proton on the aldehyde group will appear at approximately _____

Tanya [424]

Answer:

9-10 ppm.

0.2-0.4 ppm.

Explanation:

The proton on the aldehyde group will appear at approximately 9-10 ppm whereas the methylene peak on the alcohol is the only peak 0.2-0.4 ppm for either compound. Aldehydes and aromatics are quite distinctive in the Nuclear magnetic resonance (NMR). Aldehydes show up from 9-10 ppm, usually as a small singlet; aromatic protons show up from 6.5-8.5 ppm. NMR spectroscopy is the use of NMR to study the physical, chemical, and biological properties of matter.

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3 years ago

I need the answer fast pls it’s scince

harkovskaia [24]

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A 100.0-mL flask contains 0.193 g of a volatile oxide of nitrogen. The pressure in the flask is 760 mmHg at 17°C. Is the gas NO,

cestrela7 [59]

Answer:

$NO_2$

Explanation:

Considering,

$n=\frac{m}{M}$

Using ideal gas equation as:

$PV=\frac{m}{M}RT$

where,

P is the pressure = 760 mmHg

V is the volume = 100.0 mL = 0.1 L

m is the mass of the gas = 0.193 g

M is the molar mass of the gas = ?

Temperature = 17 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T = (17 + 273.15) K = 290.15 K

R is Gas constant having value = 62.36367 L. mmHg/K. mol

Applying the values as:-

$760\times 0.1=\frac{0.193}{M}\times 62.36367\times 290.15$

M = 45.95 g/mol

This mass corresponds to $NO_2$ . Hence, the gas must be $NO_2$ .

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3 years ago

Help science periodic table

romanna [79]

All the answers are on the actual periodic table. You should never be told to remember it so I think this is a recourse you are allowed to look at whilst doing your homework lol :) all the answers are written on it hope it helps

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