This equation is balanced. C + S8 -4CS2 True False

pickupchik [31]

The answer is option 2 , the smallest whole-number coefficients, the coefficient of Pb²⁺ will be 2.

What is a Balanced Chemical Equation ?

Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

There are two types of numbers that appear in chemical equations.

There are subscripts, which are part of the chemical formulas of the reactants and products;

and there are coefficients that are placed in front of the formulas to indicate how many molecules of that substance is used or produced.

Balance The Equation:

Pb²⁺ + Au²⁺ = Pb⁴⁺ + Au

Label Each Compound With a Variable

Label each compound with a variable to represent the unknown coefficients.

aPb²⁺ + bAu²⁺ = c Pb⁴⁺ + d Au

Create a System of Equations

Create an equation for each element where each term represents the number of atoms of the element in each reactant or product.

Pb: 2a + 0b = 4c + 0d

Au: 0a + 2b = 0c + 1d

e: 0a + -1b = -1c + 0d

2a - 4c = 0

2b - 1d = 0

-1b + 1c = 0

Solve For All Variables

Use substitution,

Substitute Coefficients and Verify Result

2Pb²⁺ + Au²⁺ = Pb⁴⁺ + 2 Au

So the answer is 2 , option 2

To know more about Balanced Chemical Equation

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3 0

2 years ago

Which statements describe an ideal gas?

egoroff_w [7]

Answer: B, E and F.

Explanation:

Just took a test on it and those were the correct answers.

3 0

3 years ago

The following reaction produces ethanoic acid (CHACOOH) from methanol (CH3OH) and carbon

tigry1 [53]

Answer:

$\boxed{\text{300 g}}$

Explanation:

We will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.

M_r: 32 60

CH₃OH + CO ⟶ CH₃COOH

m/g: 160

(a) Moles of CH₃OH

$\text{Moles of CH$_{3}$OH} = \text{160 g CH$_{3}$OH }\times \dfrac{\text{1 mol CH$_{3}$OH }}{\text{32 g CH$_{3}$OH}}= \text{5.00 mol CH$_{3}$OH}$

(b) Moles of CH₃COOH

$\text{Moles of CH$_{3}$COOH} = \text{5.00 mol CH$_{3}$OH } \times \dfrac{\text{1 mol CH$_{3}$COOH}}{\text{1 mol CH$_{3}$OH }} = \text{5.00 mol CH$_{3}$COOH}$

(c) Mass of CH₃COOH

$\text{Mass of CH$_{3}$COOH} =\text{5.00 mol CH$_{3}$COOH} \times \dfrac{\text{60 g CH$_{3}$COOH}}{\text{1 mol CH$_{3}$COOH}} = \textbf{300 g CH$_{3}$COOH}\\\\\text{The maximum mass of ethanoic acid that can be produced is $\boxed{\textbf{300 g}}$}$

3 0

4 years ago

A 28.5 g piece of gold is heated and then allowed to cool. What is the change in temperature (°C) if the gold releases 0.106 kJ

Shkiper50 [21]

Considering the definition of calorimetry and sensible heat, the change in temperature if the gold releases 0.106 kJ of heat as it cools is 28.78°C.

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is the amount of heat that a body absorbs or releases without any changes in its physical state (phase change). It is calculated by the expression:

Q = c× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case, you know:

Q= 0.106 kJ= 106 J (being 1 kJ=1000 J)
c= 25.4 $\frac{J}{molC}$
m= 28.5 g× $\frac{1 mole}{196.967 g}$ = 0.145 moles (being 196.967 g/mole the molar mass of gold)
ΔT= ?

Replacing:

106 J= 25.4 $\frac{J}{molC}$ × 0.145 moles× ΔT

Solving:

ΔT= $\frac{106 J}{25.4\frac{J}{molC}x0.145 moles}$

ΔT= 28.78 C

The change in temperature if the gold releases 0.106 kJ of heat as it cools is 28.78°C.

Learn more:

4 0

3 years ago

How many milliliters of 2.5 M HCl are required to exactly neutralize 1.5 L of 5.0 M NaOH?

Airida [17]

Answer:

3000mL

Explanation:

The following data were obtained from the question:

Volume of acid (Va) =..?

Molarity of acid (Ma) = 2.5M

Volume of base (Vb) = 1.5L

Molarity of base (Mb) = 5M

Next, we shall write the balanced equation for the reaction. This is given below:

HCl + NaOH —> NaCl + H2O

From the balanced equation above,

We obtained the following:

Mole ratio of the acid (nA) = 1

Mole ratio of base (nB) = 1

Next, we shall determine the volume of HCl needed for the reaction. This can be obtained as follow illustrated below:

MaVa / MbVb = nA/nB

2.5 x Va / 5 x 1.5 = 1

Cross multiply

2.5 x Va = 5 x 1.5

Divide both side by 2.5

Va = 5 x 1.5 / 2.5

Va = 3L

The volume of the acid required is 3L.

Finally, we shall convert the volume of the acid from litre (L) to millilitre (mL). This is illustrated below:

1L = 1000mL

Therefore, 3L = 3 x 1000 = 3000mL.

Therefore, the volume of the acid, HCl in mL needed fi4 the reaction is 3000mL

7 0

4 years ago