Answer:
12.2329 atm
Explanation:
Applying
PV = nRT.................... Equation 1
Make P the subject of the equation
P = (n/V)RT................ Equation 2
Where P = Osmotic pressure, (n/V) = Molarity of urea, T = Temperature, R = molar gas constant.
From the question,
Given: (n/V) = 0.5 M, T = 25°C = (273+25) = 298 K, R = 0.0821 Latm/mol.K
Substitute these values into equation 2
P = (0.5)(298)(0.0821)
P = 12.2329 atm
Question:
What type of product forms in the intramolecular reaction between the aldehyde portion of the glucose molecule below and its C-5 hydroxyl group?
a. disaccharide
b. carboxylic acid
c. hemiacetal
d. ester
e. stereoisomer
Answer:
hemiacetal forms in the intramolecular reaction between the aldehyde portion of the glucose molecule and its C-5 hydroxyl group
Explanation:
It is an alcohol also an ether that has been attached to the carbon molecule. Here the hydrogen has occupied the fourth bonding position. This hemiacetal has been derived from the aldehyde. Hence, hemiketal being an alcohol as well as ether has been attached to the same carbon and also to the two other carbon.
Answer:
B. burning a piece of wood
Explanation:
The Chemical Would Be The Air Coming From The Wood While Burning It
Tell Me If Im Correct
B and C are the correct answers
Answer:
C. CH₄ is less than NH₃ because the NH bond is more polar than the CH bond
Explanation:
The intermolecular forces between ammonia is far stronger than for methane. Between the molecules of ammonia we have the presence of hydrogen bonds. This bond is absent in methane.
Hydrogen bonds are one of the strongest intermolecular forces. It is as a result of the electrostatic attraction between the hydrogen atom of one molecule and the electronegative atom N, O and F of another molecule.
- This strong interaction is absent in methane which has just dipole - dipole attraction.
The strength of the hydrogen bond depends on the electronegativity of the combining atoms.
