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Alex_Xolod [135]
3 years ago
12

Help science periodic table

Chemistry
2 answers:
laila [671]3 years ago
5 0
Its all right here :))))

romanna [79]3 years ago
3 0
All the answers are on the actual periodic table. You should never be told to remember it so I think this is a recourse you are allowed to look at whilst doing your homework lol :) all the answers are written on it hope it helps

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ben helps his dad make chicken soup. their recipe makes 15 cups of soup. if they each eat 2 cups and freeze the rest will the le
VikaD [51]
No ,8 x 15 is 90,90-4 is 86
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4 years ago
Which kind of reaction is shown below?<br><br><br> 2H2O2 → 2H2O + O2
aleksandr82 [10.1K]
 This is a redox reaction/equation. 
3 0
3 years ago
Read 2 more answers
How many grams of nano3 would you add to 500g of h2o in order to prepare a solution that is 0.500 molal in nano3?
VARVARA [1.3K]
When the concentration is expressed in molality, it is expressed in moles of solute per kilogram of solvent. Since we are given the mass of the solvent, which is water, we can compute for the moles of solute NaNO3.

0.5 m = x mol NaNO3/0.5 kg water
x = 0.25 mol NaNO3

Since the molar mass of NaNO3 is 85 g/mol, the mass is

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4 0
3 years ago
What is the difference between cyclic compound and straight chain compound in hydrocarbons reaction​
fiasKO [112]

Explanation:

Cyclic Hydrocarbons

A cyclic hydrocarbon is a hydrocarbon in which the carbon chain joins to itself in a ring. A cycloalkane is a cyclic hydrocarbon in which all of the carbon-carbon bonds are single bonds. Like other alkanes, cycloalkanes are saturated compounds. Cycloalkanes have the general formula CnH2nCnH2n. The simplest cycloalkane is cyclopropane, a three-carbon ring.

5 0
2 years ago
How many moles of sucrose (C12H22O11) would be in 8.7 L of a 1.1 M solution of sucrose?
poizon [28]

Answer:

9.57 mol.

Explanation:

<em>Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.</em>

<em />

<em>M = (no. of moles of solute)/(V of the solution (L)).</em>

<em></em>

∴ M = (no. of moles of sucrose)/(V of the solution (L)).

1.1 M = (no. of moles of sucrose)/(8.7 L).

<em>∴ no. of moles of sucrose = (1.1 M)(8.7 L) = 9.57 mol.</em>

5 0
4 years ago
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