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3 years ago

-4.64/(-0.725) how to solve

Mathematics

2 answers:

Kipish [7]3 years ago

7 0

Answer: 6.4

Step-by-step explanation: The slash means divide and the parenthesis are there to separate the negative sign from the divide so it is not confusing

rusak2 [61]3 years ago

5 0

6.4 is the answer hope this helps

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Find the x- and y-intercepts of the line that passes through ( 3, -8) and ( -4, 13).

Ivenika [448]

Answer:

x-intercept = 1/3, y-intercept = 1

Step-by-step explanation:

y = mx + b (general equation where m=gradient, b=constant)

-8 = 3m + b (from first pair of coordinates)

13 = -4m + b (from second pair of coordinates)

3m + b - (-4m + b) = -8 - 13

7m = -21

m = -3

Using one of the linear equations above:

-8 = 3(-3) + b

-8 = -9 + b

b = 1

Therefore, the linear equation is: y = -3x + 1

To find x-intercept:

Let y = 0

0 = -3x + 1

-1 = -3x

x = 1/3

To find y-intercept:

Let x = 0

y = -3(0) + 1

y = 1

Therefore the x-intercept = 1/3 and y-intercept = 1 for the line that passes through (3, -8) and (-4, 13)

5 0

2 years ago

Evaluate: \frac{23}{56} + \frac{3}{8} - ( - \frac{4}{28} )

MrMuchimi

I think this is what you mean. I don't know why the Latex didn't work. Good for you that you can use it.

$\frac{23}{56} + \frac{3}{8} - \frac{-4}{28}$
$\frac{23}{56} + \frac{3}{8} - \frac{-4}{28}$ Reduce the 4/28 to 1/7
$\frac{23}{56} + \frac{3}{8} - \frac{-1}{7}$ Make the 2 minuses into a +
$\frac{23}{56} + \frac{3}{8} + \frac{1}{7}$ 56 is the common denominator.
$\frac{23}{56} + \frac{21}{56} + \frac{8}{56}$

Answer = [23 + 21 + 8] / 56 = 52 / 56 = 13 / 14 When both numerator and denominator are divided by 4

13 / 14 <<<< answer.

5 0

2 years ago

ASAP I NEED HELP WITH THIS QUESTION PLS

ss7ja [257]

Answer:An inverse operation are two operations that undo each other addition and subtraction or multiplication and division. You can perform the same inverse operation on each side of an equivalent equation without changing the equality. This gives us a couple of properties that hold true for all equations i guess a little bit of fraction might help if im right idk but forget the fraction part just read the other.

Step-by-step explanation: thats all i got.

8 0

3 years ago

Find the complex fourth roots of 81(cos(3pi/8) + i sin(3pi/8))

BartSMP [9]

By using De Moivre's theorem:

If we have the complex number ⇒ z = a ( cos θ + i sin θ)
∴ $\sqrt[n]{z} = \sqrt[n]{a} \ (cos \ \frac{\theta + 360K}{n} + i \ sin \ \frac{\theta +360k}{n} )$
k= 0, 1 , 2, ..... , (n-1)

For The given complex number ⇒ z = 81(cos(3π/8) + i sin(3π/8))


Part (A) find the modulus for all of the fourth roots

∴ The modulus of the given complex number = l z l = 81

∴ The modulus of the fourth root = $\sqrt[4]{z} = \sqrt[4]{81} = 3$

Part (b) find the angle for each of the four roots

The angle of the given complex number = $\frac{3 \pi}{8}$
There is four roots and the angle between each root = $\frac{2 \pi}{4} = \frac{\pi}{2}$
The angle of the first root = $\frac{ \frac{3 \pi}{8} }{4} = \frac{3 \pi}{32}$
The angle of the second root = $\frac{3\pi}{32} + \frac{\pi}{2} = \frac{19\pi}{32}$
The angle of the third root = $\frac{19\pi}{32} + \frac{\pi}{2} = \frac{35\pi}{32}$
The angle of the fourth root = $\frac{35\pi}{32} + \frac{\pi}{2} = \frac{51\pi}{32}$

Part (C): find all of the fourth roots of this

The first root = $z_{1} = 3 ( cos \ \frac{3\pi}{32} + i \ sin \ \frac{3\pi}{32})$
The second root = $z_{2} = 3 ( cos \ \frac{19\pi}{32} + i \ sin \ \frac{19\pi}{32})$

The third root = $z_{3} = 3 ( cos \ \frac{35\pi}{32} + i \ sin \ \frac{35\pi}{32})$
The fourth root = $z_{4} = 3 ( cos \ \frac{51\pi}{32} + i \ sin \ \frac{51\pi}{32})$

7 0

3 years ago

Simplify 3m/m-6 * 5m^3-30m^2/5m^2

Varvara68 [4.7K]

-30m^3-3 here is your answer

3 0

2 years ago

Read 2 more answers