A(42) = 3(42) - 8
The 42nd term is 118.
40x+8x^2=0 can be solved for x (there are two solutions):
Divide all 3 terms by the greatest common multiple (which is 8x):
40x+8x^2=0
------------- -----
8x 8x
5 + x = 0 produces the root x = - 5.
Setting 8x = 0 and solving for x produces the root x = 0.
Be certain to check these results. substitute x = -5 into 40x+8x^2=0. Is the resulting equation true or false? Next, subs. x=-5 into 40x+8x^2=0. Is the resulting equation true or false?
Hello! For ease of calculations, we can identify the time it took for the weight to bounce back to the other direction, then the other, and then back to its original position by looking at the time it took for the weight to change from 0 to 25 to 0 to -25 then back to 0. This is one whole cycle of the weight.
By the time the weight first reached zero, 1.5 seconds has passed. By the third time it got to zero again, 7.5 seconds has passed. Therefore, one whole cycle of the weight is 7.5-1.5 = 6.0 seconds.
ANSWER: One whole cycle of the weight took 6 seconds.
Answer:
1)The rocket hit the ground at 
2)The maximum height of the rocket = 12.468 feet
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given equation
y = -2 x² + 5 x + 7 ...(i)
Differentiating equation (i) with respective to 'x' , we get
Equating zero
⇒ -4 x +5 =0
⇒ -4 x = -5
⇒
<em> The rocket hit the ground at </em><em></em>
<u><em>Step(ii):</em></u>-
...(ii)
Again differentiating equation (ii) with respective to 'x' , we get
The maximum height at x = 
y = -2 x² + 5 x + 7
<em>The maximum height of the rocket = 12.468 feet</em>
