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Vikentia [17]
3 years ago
9

Please help me solve for x

Mathematics
1 answer:
ohaa [14]3 years ago
7 0

Answer:

You would do this problem like a normal varible problem. x=10

Step-by-step explanation:

Since 9x is a right angle the inside would also be 9x

9x+4x+10+40=180

180 because that is how much a triangle equals

combine like terms

13x+50=180

subtract 50 from both sides

13x=130

divide by 13

x=10

<u>Hope this helps!</u>

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Avery types a 42 word paragraph in 2/3 minute. What is her typing speed in words per
satela [25.4K]

Answer:

Step-by-ste63p explanation:

2/3 = 42

1/3 = 42 ÷ 2

     =21

3/3 is 1 min

3/3 = 21 x 3

     = 63

5 0
3 years ago
In the figure shown, ABC is a right triangle with side lengths a, b, and c, and CD is an altitude to side AB. The side lengths o
ycow [4]

Answer:

A

Step-by-step explanation:

In the figure shown, ABC is a right triangle with side lengths a, b, and c, and CD is an altitude to side AB. This altitude divides the triangle into two right triangles ADC and BDC. In these triangles,

  • \angle CBD\cong \angle ACD\cong \angle CBA
  • \angle DCB\cong \angle DAC\cong \angle BAC

So,

\triangle ABC\sim \triangle CBD\sim \triangle ACD

1. From the similarity \triangle ABC\sim \triangle CBD, you have

\dfrac{AB}{BC}=\dfrac{BC}{BD}\\ \\\dfrac{c}{a}=\dfrac{a}{s}

2. From the similarity \triangle ABC\sim \triangle ACD, you have

\dfrac{AB}{AC}=\dfrac{AC}{AD}\\ \\\dfrac{c}{b}=\dfrac{b}{r}

Hence, option A is true

5 0
3 years ago
The following table shows a portion of a five-year amortization schedule. A 5-year amortization schedule. Loan amount or princip
kogti [31]

The percentage of the payments made were due to interest is 32.6 %. Then the correct option is B.

<h3>What is the percentage?</h3>

The amount of something is expressed as if it is a part of the total which is a hundred. The ratio can be expressed as a fraction of 100. The word percent means per 100. It is represented by the symbol ‘%’.

The following table shows a portion of a five-year amortization schedule.

A 5-year amortization schedule.

Loan amount or principal: 10,900 dollars.

The interest rate on loan: 10. 95 percent.

The table will be

Month         Payment         Principal         Interest         Balance

  15               236.72            155.87            80.85           8704.27

  16               236.72            157.29            79.43           8546.98

  17               236.72            158.73            77.99            8388.25

  18               236.72            160.18            76.54            8228.07

  19               236.72            161.64            75.08            80.66.43

  20              236.72            163.11             73.61             7903.32

Total payment = 6 × 236.72 = $ 1420.32

Total interest = 80.85 + 79.43 + 77.99 + 76.56 + 75.08 + 73.61

Total interest = $ 463.38

Then the percentage will be

\rm Percentage = \dfrac{463.38}{1420.32}*100\\\\Percentage = 32.625 \approx  32.6\ \%

More about the percentage link is given below.

brainly.com/question/8011401

7 0
2 years ago
Uncle percy sold t-shirts at the show. Now he only have 10% of the t-shirts he started with. If he has 25 t-shirts now, how many
Nikitich [7]
Percy used to have 100% of the shirts (before he started selling them). Since then, he has given away 90% of the shirts and is now left with only 10% of what he used to have. He currently has 25 shirts, meaning that 25 is 10% of what he had.

Lets set up a proportion:

25 shirts : 10%
x shirts : 100%

x = 25*100 / 10
x = 2500 / 10
x = 250 shirts
Percy started off with 250 shirts.


8 0
3 years ago
Solve for the roots in simplest form by completing the square <br> 6x^2+120x+2070=0
Kitty [74]

Answer:

Step-by-step explanation:

First, we can divide out the common factor, 6

6x^2 + 120x + 2070 = 0\\x^2 + 20x + 345 = 0\\

Now we complete the square

(x^2 + 20x + (\frac{20}{2})^2) + 345 - (\frac{20}{2})^2\\(x^2 + 20x + 100) + 345 - 100\\(x+10)^2 + 245\\

(x+10)^2 = -245\\x + 10 = \sqrt{-245}\\x = i\sqrt{245}  - 10\\x = -10 \pm i\sqrt{245}

8 0
3 years ago
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