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-BARSIC- [3]
3 years ago
10

Step 1: –10 + 8x < 6x – 4

Mathematics
1 answer:
Oduvanchick [21]3 years ago
4 0
Click the link up there that answer is that
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3+6X2^3/3<br><br>Please explane me well 2^3 how can i do
victus00 [196]
Your answer would be 19
4 0
2 years ago
What multiple of 7 is also a factor of 7
enyata [817]
<span>The answer is 7. Seven is a prime number, which means that its multiples are 1 and itself (7): 7 = 1 * 7. To find out which one is a factor of 7, we should divide each of them by 7. 1/7 will be a decimal number and 7/7 = 1, which is a whole number. Thus, 7 will be a multiple of 7 and also a factor of 7.Hope this helps. Let me know if you need additional help!</span>
7 0
3 years ago
What is the length of the curve with parametric equations x = t - cos(t), y = 1 - sin(t) from t = 0 to t = π? (5 points)
zzz [600]

Answer:

B) 4√2

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Parametric Differentiation

Integration

  • Integrals
  • Definite Integrals
  • Integration Constant C

Arc Length Formula [Parametric]:                                                                         \displaystyle AL = \int\limits^b_a {\sqrt{[x'(t)]^2 + [y(t)]^2}} \, dx

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle \left \{ {{x = t - cos(t)} \atop {y = 1 - sin(t)}} \right.

Interval [0, π]

<u>Step 2: Find Arc Length</u>

  1. [Parametrics] Differentiate [Basic Power Rule, Trig Differentiation]:         \displaystyle \left \{ {{x' = 1 + sin(t)} \atop {y' = -cos(t)}} \right.
  2. Substitute in variables [Arc Length Formula - Parametric]:                       \displaystyle AL = \int\limits^{\pi}_0 {\sqrt{[1 + sin(t)]^2 + [-cos(t)]^2}} \, dx
  3. [Integrand] Simplify:                                                                                       \displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx
  4. [Integral] Evaluate:                                                                                         \displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx = 4\sqrt{2}

Topic: AP Calculus BC (Calculus I + II)

Unit: Parametric Integration

Book: College Calculus 10e

4 0
3 years ago
Evaluate: -8 over 9 + 4 over 9 - 2 over 9
stepan [7]
The answer is -2/3 from the solution above

4 0
3 years ago
Read 2 more answers
I will mark best answer brainliest
Hunter-Best [27]

Answer: -1

Step-by-step explanation:

-8 (-8x - 6) = -6x - 22

distribute

64x + 48 = -6x -22

get rid of the smallest x by adding 6x to both side

70x + 48 = -22

minus 48 to both sides

70x = -70

divide both side by 70

x = -1

8 0
2 years ago
Read 2 more answers
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