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kari74 [83]
3 years ago
9

Josh drew ∆ ABC with mm∠A = 40°, m∠B = 60° and m∠ C = 80°. Howard drew ∆ XYZ with m∠Y = 60° and m∠ Z = 80°. What can you say abo

ut the two triangles? Justify your response.
Mathematics
1 answer:
aliya0001 [1]3 years ago
7 0

Answer:

Both of these triangles are congruent.

Step-by-step explanation:

All 3 angle measures of both of the triangles are equivalent and correlate to each other. This makes the triangles congruent.

You might be interested in
The value of a boat, in dollars, x years after its purchase is represented by the function.
DIA [1.3K]
The average decrease in value can be solve by first solving the value at year 1 and year 2
and i think the equation is <span>f(x)=10,000(0.73)^x</span>

at x = 1

<span>f(x) = 10,000(0.73)^x
</span><span>f(1) = 10,000(0.73)^(1)
f(1) = 7300

at x = 2
</span><span>f(x) = 10,000(0.73)^x
</span><span>f(2) = 10,000(0.73)^(2)
f(2) = 5329

so the average decrease = ( 7300 - 5329) = $ 1971 per year</span><span>
</span>
8 0
3 years ago
Just question 1 please!!!!!
Anastaziya [24]

Answer:

see below

Step-by-step explanation:

by rewriting the function we can see that it has a minimum at

y=7x^2+7x-7\Rightarrow y=7(x^2+x-1)\Rightarrow y=7[(x+\frac{1}{2})^2-\frac{1}{4}-1]\Rightarrow

y=7[(x+\frac{1}{2})^2-\frac{5}{4}]\Rightarrow minimum \ (-\frac{1}{2}, -\frac{35}{4})

bye.

7 0
2 years ago
A ball moves in a straight line has an acceleration of a(t) = 2t + 5. Find the position function of the ball if its initial velo
Vlad1618 [11]

Answer:

s(t) = frac{t^3}{3} + \frac{5t^2}{2} - 3t + 12

Step-by-step explanation:

Relation between acceleration, velocity and position:

The velocity function is the integral of the acceleration function.

The position function is the integral of the velocity function.

Acceleration:

As given by the problem, the acceleration function is a(t) = 2t + 5

Velocity:

v(t) = \int a(t) dt = \int (2t+5) dt = \frac{2t^2}{2} + 5t + K = t^2 + 5t + K

In which K is the constant of integration, which is the initial velocity. So K = -3 and:

v(t) = t^2 + 5t - 3

Position:

s(t) = \int v(t) dt = \int (t^2 + 5t - 3) = \frac{t^3}{3} + \frac{5t^2}{2} - 3t + K

In which K, the constant of integration, is the initial position. Since it is 12:

s(t) = frac{t^3}{3} + \frac{5t^2}{2} - 3t + 12

4 0
3 years ago
Lisa surveyed 60 students at her school and found that 0.85 of the students she surveyed said their favorite class is math. Anot
Brums [2.3K]

Answer:

42

Step-by-step explanation:

Number of students whose favorite class is Math:

60*0.85=51

Number of students whose favorite class is Science:

15% is equal to 0.15.

60*0.15=9

Subtract number of students who like science from number of students who like math.

51-9=42

42 more students in the survey prefer math over science.

5 0
3 years ago
Read 2 more answers
Is there a square made up of square tiles that has only 75 squares overall? What about one that has 120 squares overall? If it i
Mama L [17]

Answer:

See below.

Step-by-step explanation:

There are two essential pieces of information missing in the question, namely:

(1) "can the the square tiles be of varying size?"

(2) "what are the number constraints on the size of a tile?" (integers only? fractional lengths? Any real number?)

Without knowing the above, I can only speculate:

If the answer is "no, the square tiles are all same size, and must be of integer size" then the answer to your question will be "no, neither with 75 nor with 120 tiles a square of integer size can be covered" This is because the numbers 75 and 120 are not perfect squares (unlike, say, 121), which is easy to check.

If the answer is "yes, the square tiles can vary in size, but must be integers" then the answer to your question will be "yes" at least in the case of the 75 tiles...I could come up with an arrangement to solve that and am positive there is one for 120. I am not going into the detail here not knowing what is really required.

If the answer is "tile size can be any real number" then the answer to your question will be "yes" (albeit, there may never be possible to construct).

Let me know if you have questions.

7 0
3 years ago
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