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Black_prince [1.1K]
3 years ago
10

What is the measure ​

Mathematics
1 answer:
monitta3 years ago
5 0

Step-by-step explanation:

x + y = 180 \\ x + 49 = 180 \\ x = 180 - 49 \\ x = 131

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The measures of one of the angles of a triangle is 35.The sum of the measures of the other two angles is 145 and the difference
jok3333 [9.3K]

Answer:

The measures of the angles are 65° and 80°

Step-by-step explanation:

One of the angles is 35°

We know that the other two angles have a difference of 15°

With this knowledge we can write an equation.

2x symbolizes the two angles

+15 symbolizes the difference between the two angles

145 = 2x + 15

145 - 15 = 130

2x = 130

x = 65

65 is the size of one of the angles.

Next, we add 15 to 65 and we get 80

80 is our second angle

8 0
4 years ago
Consider the surface defined by the equation x3 + y3 + z3 = 3xyz. Use implicit differ- ∂z entiation to find ∂x. (Note z is not a
Aloiza [94]

Answer:    

   \frac{∂z}{∂x}=\frac{(3yz-3x^{2})}{3z^{2} -3xy}

Step-by-step explanation:

Given equation is x^{3}+y^{3}+z^{3}=3xyz ………………(1)

we use derivative formula \frac{d}{dx}(x^{n})  = n x^{n-1}

\frac{d}{dx}(x^{3)}  = 3 x^{2}

\frac{d}{dx}(z^{3)}  = 3 z^{2}

And also apply 'u v' formula

\frac{d}{dx}(uv})  = u\frac{d}{dx}(v)+v\frac{d}{dx}(u)

Differentiating  equation (1) partially with respective to 'x' , we treated 'y' as constant.

(3x^{2} +0+3z^{2}\frac{∂z}{∂x}) =3y(x\frac{∂z}{∂x}+z(1))   ( here y treated as constant so the derivative of constant function is zero in addition but in multiplication the constant is keep as like 'y').

on simplification , we get

(3x^{2} +0+3z^{2}\frac{∂z}{∂x}) =(3yx\frac{∂z}{∂x}+3yz)

again simplification, we get

3z^{2}\frac{∂z}{∂x}- 3yx\frac{∂z}{∂x}=3yz-3x^{2}

taking common '\frac{∂z}{∂x} on left on side , we get

(3z^{2}- 3yx)\frac{∂z}{∂x}=3yz-3x^{2}

dividing '(3z^{2}- 3yx) on both sides, we get

\frac{∂z}{∂x}=\frac{(3yz-3x^{2})}{3z^{2} -3xy}

<u>Final answer</u>:-

\frac{∂z}{∂x}=\frac{(3yz-3x^{2})}{3z^{2} -3xy}

6 0
3 years ago
Help please describe patterns as quick as possible thank you and have a great day
NARA [144]

Answer:

40,20,10

Step-by-step explanation:

3. 640÷2=320, 360÷2=160, 160÷2=80 and so on

4 0
3 years ago
In 1927, Charles Lindburgh had his first solo flight across the Antlantic Ocean. He flew 3,610 miles in 33.5 hours. If he flew a
PolarNik [594]

Answer:

107.76

Step-by-step explanation:

We are told in the above question that:

He flew 3,610 miles in 33.5 hours. If he flew about the same number of miles each hour, how many miles did he fly each hour?

We solve the above question by:

33.5 hours = 3610 miles

1 hour = x miles

Cross Multiply

33.5 hours × x miles = 3610 miles × 1 hour

x miles = 3610 miles × 1 hour/33.5 hours

x miles = 107.76119403 miles

Approximately = 107.76 miles per hour

Therefore, he flew 107.76 miles each hour

7 0
3 years ago
How would I graph these equations?<br><br> a. 2x + 3y = 12<br><br> b. x = 7
riadik2000 [5.3K]
These are 2 very different equations, and should be graphed very differently.

<u>A
</u>
<u /><u />For Part A, we must first put this in Slope Intercept Form (SIF), which is y=mx+b where "m" is the slope and "b" is the y-intercept. To do this, we should solve like a normal equation for y.

 2x+3y=12
-2x       -2x
 3y=-2x+12
 /3        /3
y=-2/3x+4

Now that we have the proper equation, it is simply to graph! We should simply make a point at (0, 4), and then go down 2, right 3 until you are satisfied with your line.

<u>B
</u>
Part B is a simple x value, which means you will draw a vertical line through 7 on the x-axis.

Below I have attached a clearly labeled graph that shows you examples of these lines. The red markings indicate x=7. The yellow circle shows you the y-intercept in Part A, while the yellow dots show you the slope in Part A.

3 0
4 years ago
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